合作建设一个井字游戏。我试图用简单的方法成为可能。目前，我正在努力让CPU在随机选择的阵列将O在一个地方。我该如何去这样做？这是我到目前为止所。

 进口java.util.Scanner中;
导入了java.util.Random;
公共类播放器

{
    字符串球员=X;
    字符串的cpu =O;
    //私人INT [] [] theBoard =新INT [3] [3];

    私有String [] [] theBoard = {{，，}，{，，}，{，，}} ;;
    随机cpuInput =新的随机（）;

    私人董事会委员会1;
    公共静态扫描仪扫描=新的扫描仪（System.in）;

公开播放器（董事会板，字符串船内）
    {
        theBoard = theBoard;

    }

    公共无效computerMove（）
    {
        串间距=;
        的for（int i = 0; I＆LT; theBoard.length;我++）
        {
            对于（INT J = 0; J＆LT; theBoard [I] .length; J ++）
            {

                // INT随机= cpuInput.nextInt（theBoard [I] [J]）;
                theBoard [2] [2] =（CPU）; //困在这里！
            }
        }
}
 

解决方案

您需要找出主板上的可点的电脑，使一招。然后可用点之间，你可以随机选择一个使一招。

在下面的例子中，我用一个列表来存储电路板上的可用点，并使用Collections.shuffle（），以随机列表来实现做随机移动的目的。

 类点{
    INT列;
    INT关口;

    公共点（INT行，诠释列）{
        this.row =行;
        this.col =关口;
    }
}

公共无效computerMove（）{
    串间距=;

    //首先找出可移动的电脑
    名单＆LT;点＆GT; availableSpots =新的ArrayList＆LT;＆GT;（）;
    的for（int i = 0; I＆LT; theBoard.length ++我）{
        对于（INT J = 0; J＆LT; theBoard [I] .length; ++ j）条{
            如果（theBoard [I] [J]。.equals（间距））{
                availableSpots.add（新点（I，J））;
            }
        }
    }

    //如果没有可用的动作，什么都不做，游戏已经结束
    如果（availableSpots.isEmpty（））{
        的System.out.println（没有更多的斑点可用在黑板上。）;
        返回;
    } 其他 {
        //洗牌的名单，使之成为随机orderedd
        Collections.shuffle（availableSpots）;

        //获取随机列表中的第一个
        现货现货= availableSpots.get（0）;
        theBoard [spot.row] [spot.col] =（CPU）;
    }
}
 

Working on building a tic tac toe game. I'm trying to use as simple of methods as possible. I'm currently working on getting the cpu to randomly choose a spot in the array to place the "O" at. How do I go about doing this? This is what I have so far.

import java.util.Scanner;
import java.util.Random;
public class Player

{
    String player = "X";
    String cpu = "O";
    //private int[][] theBoard= new int [3][3] ;

    private String[][] theBoard=  {{" "," "," "}, {" "," "," "}, {" ", " "," "}};;
    Random cpuInput = new Random(); 

    private Board board1;
    public static Scanner scan = new Scanner(System.in);

public Player(Board board, String inBoard )
    {
        theBoard = theBoard;

    }

    public void computerMove()
    {
        String spacing = " ";
        for (int i = 0; i < theBoard.length; i++)
        {
            for (int j = 0; j < theBoard[i].length; j++)
            {

                //int random = cpuInput.nextInt(theBoard[i][j]);
                theBoard[2][2] = (cpu); //STUCK HERE!                
            }
        }
}

You need to find out the available spots on the board for computer to make a move. Then among the available spots you can randomly choose one to make a move.

In the below example, I use a list to store the available spots on the board and use Collections.shuffle() to randomize the list to achieve the purpose of making a random move.

class Spot {
    int row;
    int col;

    public Spot(int row, int col) {
        this.row = row;
        this.col = col;
    }
}

public void computerMove() {
    String spacing = " ";

    // firstly finding out the available moves for the computer
    List<Spot> availableSpots = new ArrayList<>();
    for (int i = 0; i < theBoard.length; ++i) {
        for (int j = 0; j < theBoard[i].length; ++j) {
            if (theBoard[i][j].equals(spacing)) {
                availableSpots.add(new Spot(i, j));
            }
        }
    }

    // if no available moves, do nothing, game has ended
    if (availableSpots.isEmpty()) {
        System.out.println("No more spots available on the board.");
        return;
    } else {
        // shuffle the list so that it becomes randomly orderedd
        Collections.shuffle(availableSpots);

        // get the first one of the random list
        Spot spot = availableSpots.get(0);
        theBoard[spot.row][spot.col] = (cpu);
    }
}