我想了一个方法来比较DATE2（现在的）日期1（2013年1月21日二十一时22分30秒）

我想获得多少日期，小时，分钟和秒形式剩余1日

 字符串mDate，mHour，mMinute，mSecond;DateComparedateTime（字符串日期1）{ //现在用比较日期1   mDate =差日期date1和现在;   mHour =与date1和现在差别小时;   mMinute =差与分钟date1和现在;   mSecond =差第二，date1和现在;} 

如何创造这个方法？

 日历的currentdate = Calendar.getInstance（）;      SimpleDateFormat的SDF =新的SimpleDateFormat（MM / DD / YYYY）;    串dateNow = sdf.format（currentDate.getTime（））;      今天的日期=新的日期（dateNow）;      日期finalDay = NULL;      finalDay =（日期）sdf.parse（MM / DD / YYYY）;    INT NUMBEROFDAYS =（int）的（（finalDay.getTime（） -  today.getTime（））/（3600 * 24 * 1000））; 

I want to compare date1(2013/1/21 21:22:30) with date2(now) in one method

I want to get how much date,hours,minutes and second Remaining form Date 1

String mDate,mHour,mMinute,mSecond;

DateComparedateTime(String Date1)
{
 // compare  Date1 with now 
   mDate = Difference date with Date1 and Now;
   mHour = Difference hour with Date1 and Now;
   mMinute = Difference minute with Date1 and Now;
   mSecond = Difference second with Date1 and Now;
}

how can create this method ?

Calendar currentDate = Calendar.getInstance();
      SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");


    String dateNow = sdf.format(currentDate.getTime());
      Date today =  new Date(dateNow);
      Date finalDay = null;
      finalDay = (Date) sdf.parse("MM/dd/yyyy");
    int numberOfDays=(int)((finalDay.getTime()-today.getTime())/(3600*24*1000));