我已经检查了我的EditText是Android中可见或不可见。

现在我要检查的条件。

如果我的EditText是可见的方式我怎样才能插入数据。 如果我的EditText消失意味着我怎么可以插入另一个数据。

这是我的$ C $下，如果我要选中复选框意味着EditText上是看不到的，否则的EditText是可见的：

  chkIos =（复选框）findViewById（R.id.addresscheckbox）;

    chkIos.setOnClickListener（新View.OnClickListener（）{
      公共无效的onClick（视图v）{
        如果（（（复选框）V）.isChecked（））
        {
             S_address =（TextView中）findViewById（R.id.address1）;
             S_address.setVisibility（View.GONE）;

        Saddress =（EditText上）findViewById（R.id.tf_address1）;
        Saddress.setVisibility（View.GONE）;
      }
        其他
        {
             S_address =（TextView中）findViewById（R.id.address1）;
             S_address.setVisibility（View.VISIBLE）;

       Saddress =（EditText上）findViewById（R.id.tf_address1）;
        Saddress.setVisibility（View.VISIBLE）;
        如果（！（Saddress.getText（）的toString（）长度（）== 0））{

                showAlertbox（送货地址是必需的！）;
            }
      }
 

下面code是，如果我的EditText是可见的方式插入到saddr value.otherwise插入baddr value.how我可以检查的条件。

下面以下错误显示： 可见不能被解析为一个变量。

 如果（Saddress ==可见）
    {
        的PropertyInfo saddress =新的PropertyInfo（）;
        saddress.setName（Saddress）; //定义在Web服务方法的变量名
        saddress.setValue（SADDR）; //定义值FNAME变量
        saddress.setType（为String.class）; //定义变量的类型
        request.addProperty（saddress）; //通行证属性到可变

    }
    其他
    {
    的PropertyInfo saddress =新的PropertyInfo（）;
    saddress.setName（Saddress）; //定义在Web服务方法的变量名
    saddress.setValue（baddr）; //定义值FNAME变量
    saddress.setType（为String.class）; //定义变量的类型
    request.addProperty（saddress）; //通行证属性到可变
    }
 

请参阅完整的源代码code在这里：满code

编辑：

在我的codeI必须选中复选框意味着Saddress是无形的know.that时候，我必须按一下按钮意味着插入baddr值...如果我不得不取消选中该复选框意味着Saddress值visible.that时候我已经插入SADDR值。

在这里，我需要运行的应用程序意味着baddr值insered两个Saddress ==可见和Saddess ==无形case.how可我写的条件这些。

解决方案

使用

 如果（Saddress.getVisibility（）== View.VISIBLE）{
  // ..您的code在这里
}
 

而不是

 如果（Saddress ==可见）{
// ..您的code在这里
}
 

由于可见， GONE 和看不见的一部分View类，而不是活性

I have checked my edittext is visible or invisible in android.

Now i have to check the condition is.,

If my edittext is visible means how can i insert the data. If my edittext is gone means how can i insert on another data.

This is my code for if i have to check the checkbox means the edittext is invisible otherwise the edittext is visible .:

 chkIos = (CheckBox) findViewById(R.id.addresscheckbox);

    chkIos.setOnClickListener(new View.OnClickListener() {
      public void onClick(View v) {
        if (((CheckBox) v).isChecked())
        {
             S_address = (TextView)findViewById(R.id.address1);  
             S_address.setVisibility(View.GONE);  

        Saddress = (EditText)findViewById(R.id.tf_address1);  
        Saddress.setVisibility(View.GONE);  
      }
        else
        {
             S_address = (TextView)findViewById(R.id.address1);  
             S_address.setVisibility(View.VISIBLE);  

       Saddress = (EditText)findViewById(R.id.tf_address1);  
        Saddress.setVisibility(View.VISIBLE);
        if(!(Saddress.getText().toString().length() == 0)){

                showAlertbox(" Shipping Address is Required!!"); 
            }
      }

The below code is ., if my edittext is visible means insert the saddr value.otherwise insert the baddr value.how can i check the condition.

Here below error is showing: VISIBLE cannot be resolved to a variable.

      if(Saddress== VISIBLE)
    {
        PropertyInfo saddress =new PropertyInfo();
        saddress.setName("Saddress");//Define the variable name in the web service method
        saddress.setValue(saddr);//Define value for fname variable
        saddress.setType(String.class);//Define the type of the variable
        request.addProperty(saddress);//Pass properties to the variable

    }
    else
    {
    PropertyInfo saddress =new PropertyInfo();
    saddress.setName("Saddress");//Define the variable name in the web service method
    saddress.setValue(baddr);//Define value for fname variable
    saddress.setType(String.class);//Define the type of the variable
    request.addProperty(saddress);//Pass properties to the variable
    }

please see the full source code here:full code

EDIT:

In my code i have to check the checkbox means the Saddress is invisible know.that time i have to click the button means the baddr value is inserted...If i have to uncheck the checkbox means the Saddress value is visible.that time i have to insert the saddr value.

Here i have to run the app means the baddr value is insered both Saddress==visible and Saddess==invisible case.how can i write the condition for these.

解决方案

use

if(Saddress.getVisibility() == View.VISIBLE){
  //.. your code here
}

instead of

if(Saddress== VISIBLE){
//.. your code here
}

because VISIBLE,GONE and INVISIBLE is part of View class instead of Activity