我期待建立一个通用的程序，将工作在一个视图的孩子。在例行我需要能够遍历子视图。我没有看到任何的API中，将表明，有什么办法让孩子的意见。有一个添加（）和删除（）方法，但没有像获得（）也没有，似乎有像意见的任何属性。我在想什么？

I am looking to create a general purpose routine that will operate over a view's children. Within the routine I need to be able to iterate over the child views. I don't see anything in the API that would suggest that there is any way to get the child views. There is an "add()" and a "remove()" method but nothing like "get()" nor does there appear to be any properties like "views". What am I missing?

推荐答案

这是基本的结构去除孩子从视图对象

this is the basic structure for removing child objects from a view

    if (view.children) {
        for (var c = view.children.length - 1; c >= 0; c--) {
            view.remove(view.children[c]);
        }
    }