I am sending a gzip file from Postman to a Flask endpoint. I can take that binary file with request.data
and read it, save it, upload it, etc.
My problem is that I can't take its name. How can I do that?
My gzip file is called "test_file.json.gz" and my file is called "test_file.json".
How can I take any of those names?
Edit:
I'm taking the stream data with io.BytesIO(), but this library doesn't contain a name attribute or something, although I can see the file name into the string if I just:
>>>print(request.data)
>>>b'x1fx8bx08x08xcaxb1xd3]x00x03test_file.jsonx00xabxe6RPPxcaNxad4Txb2RP*Kxcc)M5Txe2xaax05x00xc2x8bxb6;x16x00x00x00'
解决方案
Further to the comment, I think the code which handles your upload is relevant here.
See this answer regarding request.data
:
request.data
Contains the incoming request data as string in case it came with a mimetype Flask does not handle.
The recommended way to handle file uploads in flask is to use:
file = request.files['file']
file
is then of type: werkzeug.datastructures.FileStorage
.
file.stream
is the stream, which can be read with file.stream.read()
or simply file.read()
file.filename
is the filename as specified on the client.
file.save(path)
a method which saves the file to disk. path
should be a string like '/some/location/file.ext'
source