我要返回游标的方法，但它不幸滋生出于某种原因NullPointerException异常。

这里的方法，有什么错呢？

 公共光标getRandom（字符串tableName值）{        返回db.query（tableName值+ORDER BY RANDOM（）LIMIT 1，新的String [] {KEY_ID，KEY_TEXT}，NULL，NULL，NULL，NULL，NULL）;    } 

解决方案

按声明的顺序是在错误的地方。

  SQLiteDatabase.query（字符串表，字符串[]栏，选择字符串，字符串[] selectionArgs两个，字符串GROUPBY，有字符串，字符串的OrderBy，字符串限制）。 

看看在 API 。

I have a method to return a Cursor, however it unfortunately spawns a NullPointerException for some reason.

Here's the method, is there anything wrong with it?:

public Cursor getRandom(String tableName) {
        return db.query(tableName + " Order BY RANDOM() LIMIT 1", new String[] {KEY_ID, KEY_TEXT}, null, null, null, null, null);
    }

The order by statement is in the wrong place.

SQLiteDatabase.query(String table, String[] columns, String selection, String[] selectionArgs, String groupBy, String having, String orderBy, String limit).

Take a look at the API.