我的工作中，我使用咂嘴库即时通讯一切正常，但巨大的问题是在订阅的机器人聊天应用程序。

I am working on an android chat application in which i am using smack library for instant messaging everything is working fine but the huge problem is in subscription.

如何发送订阅通知给其他用户。

How to send subscription notification to another user.

这是我的code发送订阅请求：

public void run() {
        /*runOnUiThread(new Runnable() {
            public void run() {*/
                Roster roster = XMPPSmackConnection.getInstance().connection.getRoster();
                roster.setSubscriptionMode(Roster.SubscriptionMode.manual);
                try {
                    if(!_userName.contains("@"))
                        _userName=_userName+"@www.naijapings.net";

                    /*Presence presence = (Presence) packet;
                    Presence presence_request = new Presence(Presence.Type.subscribed);
                    presence_request.setTo(presence.getFrom());
                    presence_request.setType(Presence.Type.subscribed);
                    presence_request.setFrom("current_logged_in_user");
                    XMPPSmackConnection.getInstance().connection.sendPacket(presence_request);
                    roster.createEntry(presence.getFrom(), null, null);*/

                    /*Presence response = new Presence(Presence.Type.subscribe);
                    response.setTo(_userName);
                    XMPPSmackConnection.getInstance().connection.sendPacket(response);*/

                    //PROCESS TWO WAY COMMUNICATION
                    Presence response1 = new Presence(Presence.Type.subscribe);
                    response1.setTo(_userName);
                    XMPPSmackConnection.getInstance().connection.sendPacket(response1);
                    //////////////////////////////////////////////////////

                    //roster.createEntry(_userName, null, null);

                    /*roster.createEntry(_userName, _nickName, Friends);*/
                    //roster.createEntry(_tempUserName, null, null);
                    //roster.createEntry(_userName, _nickName, my_friends[]);
                    //addBuddy(_userName, _nickName, Friends);
                } catch (Exception e) {
                    _progDailog.dismiss();
                    e.printStackTrace();
                }
                _progDailog.dismiss();
                successAlert("Buddy requested successfully");
            /*}
        });*/

以上code只能建立名册进入其他用户的阵容名单，但没有表现出认购通知。

The above code only create roster entry to other user's roster list but not showing subscription notification.

下面是code接受预订请求：

runOnUiThread(new Runnable() {
                public void run() {
                    try {
                        Roster roster = XMPPSmackConnection.getInstance().connection.getRoster();
                        ///roster.setSubscriptionMode(Roster.SubscriptionMode.manual);
                        //Presence presence = roster.getPresence(_buddyUserName);
                        roster.setSubscriptionMode(Roster.SubscriptionMode.manual);
                        //Presence subscribed = new Presence(Presence.Type.subscribed);

                        Presence response = new Presence(Presence.Type.subscribed);
                        response.setTo(_buddyUserName);
                        XMPPSmackConnection.getInstance().connection.sendPacket(response);

                        /*response = new Presence(Presence.Type.subscribed);
                        response.setTo(_buddyUserName);
                        XMPPSmackConnection.getInstance().connection.sendPacket(response);*/

                        roster.createEntry(_buddyUserName, _nickNameEditText.getText().toString(), Friends);
                    } catch (Exception e) {
                        e.printStackTrace();
                    }
                }
            });

请建议确切的情况。

推荐答案

好了，我辛苦劳碌在这几天，最后得到的东西的工作。我已经实现了它与手动订阅模式（即用户需要接受其他用户的请求，以手动）。

Okay, I toiled hard at this for a couple of days and finally got things working. I have implemented it with a manual subscription mode (ie. user needs to accept another user's request manually).

服务器保留推订阅请求给用户（在重新登录），如果用户未发送订阅或退订回来。那么，你能做的就是在本地保存收到的认购请求在列表中，并显示为好友请求列表手工接受/拒绝。如果您的应用程序被重新启动（并因此重新连接到服务器），服务器将再次推订阅请求。

The server keeps pushing subscribe request to the user (upon re-login) if the user hasn't sent a subscribed or unsubscribed back. So what you can do is save the incoming subscribe requests locally in a list and display that as a "friend request list" for manual accept/reject. If your application gets restarted (and hence re-connects to server), the server will push subscribe requests again.

这是如何工作的：

在用户1发送订阅presence到用户2。 进入名册就会自动在用户1的花名册创建（而不是在用户2的名册）。 用户2接收来自用户1订阅的请求。 在用户2发回订阅presence到用户2（用户2>用户1认购完成）。 在用户2检查，如果用户1在用户2的花名册。用户1是不是在用户2的花名册。用户2发回一个认购presence为user1。 进入名册就会自动在用户2的花名册创建。 在用户1接收订阅presence从用户2。

用户1检查，如果用户2是在用户1的花名册。用户2在用户1的花名册。用户1发回一个订阅presence到用户2（用户2>用户1认购完成）。 User1 sends subscribe presence to User2. Roster entry gets automatically created in User1's roster (but not in User2's roster). User2 receives subscribe request from User1. User2 sends back a subscribed presence to User2 (User2 > User1 subscription complete). User2 checks if User1 is in User2's roster. User1 is not in User2's roster. User2 sends back a subscribe presence to User1. Roster entry gets automatically created in User2's roster. User1 receives subscribe presence from User2.

User1 checks if User2 is in User1's roster. User2 is in User1's roster. User1 sends back a subscribed presence to User2 (User2 > User1 subscription complete).

        final Presence newPresence = (Presence) packet;
        final Presence.Type presenceType = newPresence.getType();
        final String fromId = newPresence.getFrom();
        final RosterEntry newEntry = getRoster().getEntry(fromId);

        if (presenceType == Presence.Type.subscribe)
        {
            //from new user
            if (newEntry == null)
            {
                //save request locally for later accept/reject
                //later accept will send back a subscribe & subscribed presence to user with fromId
                //or accept immediately by sending back subscribe and unsubscribed right now
            }
            //from a user that previously accepted your request
            else
            {
                //send back subscribed presence to user with fromId
            }
        }