我一共停电,我不熟悉的片段工作。
我与Eclipse助手创建了一个新的Android项目:
在这里创建的默认类的一个片段:
/ ** * A {@link FragmentPagerAdapter}返回对应片段 *章节/标签/页面。 * /公共类SectionsPagerAdapter扩展FragmentPagerAdapter { 公共SectionsPagerAdapter(FragmentManager FM){ 超(FM); } @覆盖 公共片段的getItem(INT位置){ //的getItem被称为实例化片段为给定的页面。 //返回一个PlaceholderFragment(定义为静态内部类 //下面)。 返回PlaceholderFragment.newInstance(位置+ 1); } @覆盖 公众诠释的getCount(){ //显示3总页数。 返回3; } @覆盖 公共CharSequence的getPageTitle(INT位置){ 区域设置L = Locale.getDefault(); 开关(位置){ 情况下0: 返回的getString(R.string.title_section1).toUpperCase(升); 情况1: 返回的getString(R.string.title_section2).toUpperCase(升); 案例2: 返回的getString(R.string.title_section3).toUpperCase(升); } 返回null; }}/ ** *包含一个简单视图中的占位符片段。 * /公共静态类PlaceholderFragment扩展片段{ / ** *片段参数重新presenting本节号 *片段。 * / 静态INT秒; 私有静态最后弦乐ARG_SECTION_NUMBER =SECTION_NUMBER; / ** *返回该片段对于给定部分数的新实例。 * / 公共静态的newInstance PlaceholderFragment(INT sectionNumber){ 秒= sectionNumber; Log.i(ARG_SECTION_NUMBER,+秒); PlaceholderFragment片段=新PlaceholderFragment(); 捆绑ARGS =新包(); args.putInt(ARG_SECTION_NUMBER,sectionNumber); fragment.setArguments(参数); 返回片段; } 公共PlaceholderFragment(){ } @覆盖 公共查看onCreateView(LayoutInflater充气器,容器的ViewGroup, 捆绑savedInstanceState){ INT JJJ =秒; Log.i(onCreateView,+秒); 查看rootView = inflater.inflate(R.layout.fragment_main,集装箱, 假); 返回rootView; }}
的 SectionsPagerAdapter用作适配器,并返回片段3个片段都具有相同的布局
fragment_main.xml
如何能分配到3个片段不同的布局?
在PlaceholderFragment包含一个捆绑的SECTION_NUMBER:
args.putInt(ARG_SECTION_NUMBER,sectionNumber);
我可以使用此信息为determing至极布局在每个片段中显示?
//创建一个将返回一个片段为三个的适配器 //活性的主要部分。 mSectionsPagerAdapter =新SectionsPagerAdapter( getSupportFragmentManager()); //设置的ViewPager与部分适配器。 mViewPager =(ViewPager)findViewById(R.id.pager); mViewPager.setAdapter(mSectionsPagerAdapter);
解决方案
您需要让不同类别的每一页。一个页面从片段延伸。您只需加载不同的布局XML为每个片段。
公共类FirstFragment扩展片段{@覆盖公共查看onCreateView(LayoutInflater充气器,容器的ViewGroup, 捆绑savedInstanceState){ 查看rootView = inflater.inflate(R.layout< yourxmlhere>中容器, 假); 返回rootView;}}
您知道有片段,但你仍然适配器需要知道哪些页面(位置)是片段。这在下面的函数决定:
@覆盖公共片段的getItem(INT位置){ 开关(位置){ 情况下0: //第1页 返回新FirstFragment(); 打破; 情况1: //第2页 返回新SecondFragment(); 打破; 默认: //这个页面不存在 返回null;}
请确保您已设置页面的正确数量!
@覆盖公众诠释的getCount(){ //页面的数量适配器知道 返回< youramountofpages取代;}
这应该让你和运行。
编辑:您可以只删除整个placeholderfragment类。它不再需要。
I have a total blackout, I am not familiar to work with fragments.
I created with the eclipse assistant a new Android project:
here a snippet of the created default class:
/**
* A {@link FragmentPagerAdapter} that returns a fragment corresponding to
* one of the sections/tabs/pages.
*/
public class SectionsPagerAdapter extends FragmentPagerAdapter {
public SectionsPagerAdapter(FragmentManager fm) {
super(fm);
}
@Override
public Fragment getItem(int position) {
// getItem is called to instantiate the fragment for the given page.
// Return a PlaceholderFragment (defined as a static inner class
// below).
return PlaceholderFragment.newInstance(position + 1);
}
@Override
public int getCount() {
// Show 3 total pages.
return 3;
}
@Override
public CharSequence getPageTitle(int position) {
Locale l = Locale.getDefault();
switch (position) {
case 0:
return getString(R.string.title_section1).toUpperCase(l);
case 1:
return getString(R.string.title_section2).toUpperCase(l);
case 2:
return getString(R.string.title_section3).toUpperCase(l);
}
return null;
}
}
/**
* A placeholder fragment containing a simple view.
*/
public static class PlaceholderFragment extends Fragment {
/**
* The fragment argument representing the section number for this
* fragment.
*/
static int sec;
private static final String ARG_SECTION_NUMBER = "section_number";
/**
* Returns a new instance of this fragment for the given section number.
*/
public static PlaceholderFragment newInstance(int sectionNumber) {
sec = sectionNumber;
Log.i("ARG_SECTION_NUMBER"," "+sec);
PlaceholderFragment fragment = new PlaceholderFragment();
Bundle args = new Bundle();
args.putInt(ARG_SECTION_NUMBER, sectionNumber);
fragment.setArguments(args);
return fragment;
}
public PlaceholderFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
int jjj = sec;
Log.i("onCreateView"," "+sec);
View rootView = inflater.inflate(R.layout.fragment_main, container,
false);
return rootView;
}
}
the SectionsPagerAdapter is used as an adapter and is returning Fragments the 3 fragments are having all the same layout
fragment_main.xml
how can different layouts assigned to the 3 fragments?
the PlaceholderFragment contains a Bundle with the section_number:
args.putInt(ARG_SECTION_NUMBER, sectionNumber);
can I use this Info for determing wich layout to show in each fragment?
// Create the adapter that will return a fragment for each of the three
// primary sections of the activity.
mSectionsPagerAdapter = new SectionsPagerAdapter(
getSupportFragmentManager());
// Set up the ViewPager with the sections adapter.
mViewPager = (ViewPager) findViewById(R.id.pager);
mViewPager.setAdapter(mSectionsPagerAdapter);
解决方案
You need to make different classes for each page. A page extends from a Fragment. You can just load a different layout-xml for every fragment.
public class FirstFragment extends Fragment{
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.<yourxmlhere>, container,
false);
return rootView;
}
}
You know have the fragment, but your adapter still needs to know which page (position) is which fragment. This is decided in the following function:
@Override
public Fragment getItem(int position) {
switch (position){
case 0:
//page 1
return new FirstFragment();
break;
case 1:
//page 2
return new SecondFragment();
break;
default:
//this page does not exists
return null;
}
Make sure you have set the correct amount of pages!
@Override
public int getCount() {
//the amount of pages your adapter knows
return <youramountofpages>;
}
This should get you up and running.
EDIT: You can just delete the whole placeholderfragment class. It is not needed anymore.