我已经创建了显示从水库全部内容的应用程序/文件夹原料

I have created a app that displays all the content from res/raw folder.

我要当我的.doc文件单击它应该打开，我可以查看其内容。

I need that when i click on .doc file it should open and I can view its content.

请帮我。

我有ThinkFree的。

I have ThinkFree.

enter code here
public class FileList extends ListActivity {

public static final Field[] fields = R.raw.class.getFields();

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setListAdapter(new ArrayAdapter<Field>(this, R.layout.row, R.id.weekofday, fields));
}

@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
    // TODO Auto-generated method stub
    //super.onListItemClick(l, v, position, id);
    String selection = l.getItemAtPosition(position).toString();
    Toast.makeText(this, selection, Toast.LENGTH_SHORT).show();

    Intent i = new Intent();
    i.setAction(android.content.Intent.ACTION_VIEW);
    startActivity(i);
}

}

推荐答案

您想要什么是不可能的。第三方应用程序将无法读取Word文档出您的原始资源。

What you want is not possible. A third-party application will not be able to read a Word document out of your raw resources.

目前最好的，你可以将文件从原始资源的某个地方（例如，外部存储），然后调用拷贝 startActivity（）上的 ACTION_VIEW 意图具有乌里指向可读的拷贝，也有正确的MIME类型

At best, you could copy the file from the raw resource someplace (e.g., external storage), then call startActivity() on an ACTION_VIEW Intent that has a Uri pointing to the readable copy and also has the proper MIME type.

当然，这只是上有一个Word文档浏览器的设备上工作。

Of course, this will only work on a device that has a Word document viewer on it.