我有一组三个单选按钮.根据选择的单选按钮，我想显示三个控件之一 - 文本框、下拉列表或按钮.如何根据选定单选按钮的结果显示控件?

I have a group of three radio buttons. Depending on which radio button is selected, I want to disaply one of three controls - a textbox, a dropdown list, or a button. How do I display controls based on the result of a selected radio button?

推荐答案

您可以使用 BooleanToVisibilityConverter 将控件的可见性绑定到 RadioButton 的 IsChecked 属性:

You can bind the visibility of the control to the IsChecked property of the RadioButton, using the BooleanToVisibilityConverter :

<Page
  xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
  xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
  <Page.Resources>
    <BooleanToVisibilityConverter x:Key="convVisibility"/>
  </Page.Resources>
  <Grid>
    <StackPanel Orientation="Vertical">
      <RadioButton Name="radioButton1" GroupName="group1">Control1</RadioButton>
      <RadioButton Name="radioButton2" GroupName="group1">Control2</RadioButton>
      <RadioButton Name="radioButton3" GroupName="group1">Control3</RadioButton>
      <Grid>
        <Button Visibility="{Binding IsChecked, ElementName=radioButton1, Converter={StaticResource convVisibility}}">1. Button</Button>
        <TextBlock Visibility="{Binding IsChecked, ElementName=radioButton2, Converter={StaticResource convVisibility}}">2. TextBlock</TextBlock>
        <TextBox Visibility="{Binding IsChecked, ElementName=radioButton3, Converter={StaticResource convVisibility}}">3. TextBox</TextBox>
      </Grid>
    </StackPanel>
  </Grid>
</Page>

该解决方案效果很好，并且易于实施.无论如何我可以防止控件在设计模式下被隐藏?

That solutions works great and it's simple to implement. Is there anyway I can prevent the controls from being hidden in design mode?

我不了解其他设计器(例如 Blend)，但在 Visual Studio 设计器中，控件从不隐藏...

I don't know about other designers (Blend for instance), but in the Visual Studio designer the controls are never hidden...

无论如何，您可以实现自己的转换器，该转换器在设计模式下始终返回 Visible.由于某种晦涩的原因， BooleanToVisibilityConverter 类是密封的，因此您不能从它继承.如果您不想重写转换逻辑，则可以将转换委托给 BooleanToVisibilityConverter:

Anyway, you could implement your own converter, which would always return Visible in design mode. For some obscure reason the BooleanToVisibilityConverter class is sealed, so you can't inherit from it. You can delegate the conversion to a BooleanToVisibilityConverter instead, if you don't want to rewrite the conversion logic :

public class MyBooleanToVisibilityConverter : IValueConverter
{
    private BooleanToVisibilityConverter _converter = new BooleanToVisibilityConverter();
    private DependencyObject _dummy = new DependencyObject();

    private bool DesignMode
    {
        get
        {
            return DesignerProperties.GetIsInDesignMode(_dummy);
        }
    }

    #region IValueConverter Members

    public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        if (DesignMode)
            return Visibility.Visible;
        else
            return _converter.Convert(value, targetType, parameter, culture);
    }

    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        return _converter.ConvertBack(value, targetType, parameter, culture);
    }

    #endregion
}