有什么用ActivityManager.isUserAMonkey（）方法？

  ActivityManager.isUserAMonkey（）
 

解决方案

它会告诉你，如果用户是测试猴子还是猴子亚军。 孙悟空是一个命令行工具，你可以在任何模拟器或设备上运行。它发送用户事件的伪随机流进入系统，它作为你正在开发的应用软件压力测试。

您可以使用它这样的：

 公共布尔wasItTheMonkey（）{

     ActivityManager activityManager =（ActivityManager）getSystemService（Context.ACTIVITY_SERVICE）;

     如果（activityManager.isUserAMonkey（））{

           Log.d（TAG，这是猴子）;
           返回true;

     }

     Log.d（TAG，这是一个用户）;
     返回false;
}
 

请参阅这里

what is the use of ActivityManager.isUserAMonkey() method?

ActivityManager.isUserAMonkey()

It will tell you if the user is the Test Monkey or the monkey runner. "The Monkey is a command-line tool that that you can run on any emulator instance or on a device. It sends a pseudo-random stream of user events into the system, which acts as a stress test on the application software you are developing."

You can use it like that:

public boolean wasItTheMonkey(){

     ActivityManager activityManager =  (ActivityManager)getSystemService(Context.ACTIVITY_SERVICE);

     if(activityManager.isUserAMonkey()) {

           Log.d(TAG,"it was the monkey");
           return true;

     }

     Log.d(TAG,"it was an user");
     return false;
}

See here.