那么的Int32没有一个==操作符，但这是有效的code

 布尔Y = 6 = = 5;
 

这是因为的Int32是原始类型集的一部分。它有效地汇集到CEQ在IL。

所以，给出的类型（与反思）怎么可能是类型支持CEQ当它没有==操作符是确定？

该规范说（§7.10）：

在predefined整数比较操作符是：

 布尔运算符==（INT X，int y）对;
布尔运算符==（UINT X，UINT Y）;
布尔运算符==（长×长Y）;
布尔运算符==（ULONG X，ULONG y）的;
 

在predefined浮点比较运算符是：

 布尔运算符==（浮X，浮动Y）;
布尔运算符==（双X，双Y）;
 

在predefined小数比较运算符：

 布尔运算符==（十进制的x，小数Y）;
布尔运算符=（十进制X，小数Y）！;
 

在predefined布尔相等运算符为：

 布尔运算符==（BOOL X，布尔Y）;
布尔运算符=（BOOL X，布尔Y）！;
 

每个枚举类型都隐式提供pdefined以下$ P $   比较运算：

 布尔运算符==（E X，E Y）;
布尔运算符=（E X，E Y）！;
 

注意 decimal.operator == 是正常的方法，而不是一个内置的操作。我不知道为什么它列出。

So Int32 does not have an == operator but this is valid code

bool y = 6 == 5;

This is because Int32 is part of the primitive set of types. It effectively compiles to CEQ in IL.

So given a Type (with reflection) how can it be determined that that type supports CEQ when it has no == operator?

The spec says (§7.10):

The predefined integer comparison operators are:

bool operator ==(int x, int y);
bool operator ==(uint x, uint y);
bool operator ==(long x, long y);
bool operator ==(ulong x, ulong y);

The predefined floating-point comparison operators are:

bool operator ==(float x, float y);
bool operator ==(double x, double y);

The predefined decimal comparison operators are:

bool operator ==(decimal x, decimal y);
bool operator !=(decimal x, decimal y);

The predefined boolean equality operators are:

bool operator ==(bool x, bool y);
bool operator !=(bool x, bool y);

Every enumeration type implicitly provides the following predefined comparison operators:

bool operator ==(E x, E y);
bool operator !=(E x, E y);

Note that decimal.operator == is a normal method, not a built-in operator. I'm not sure why it's listed there.