我想使用 Jersey 来实现一些 Java REST 服务.默认的 POJO 转换器 JAXB 处理 JSON 对象有点奇怪，所以我想使用 Jackson 来转换 POJO，开销很小或更少.如何告诉 J2ME 框架使用另一个转换器?

I want to use Jersey for implemnting some Java REST services. The default POJO converter JAXB handles JSON objects a bit strange, so I want to use Jackson for converting POJOs with little or less overhead. How would do I tell the J2ME framework to use another converter?

我的 web.xml 看起来像这样:

My web.xml looks like this:

<!-- Jersey JAVA REST implementation -->
<servlet>
<servlet-name>Jersey</servlet-name>
    <servlet-class>
        com.sun.jersey.spi.container.servlet.ServletContainer
    </servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>org.foobar.rest.services</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>Jersey</servlet-name>
    <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

推荐答案

只需像这样添加jackson JAR并修改web.xml:

simply add the jackson JARs and modify the web.xml like this:

<!-- Jersey JAVA REST implementation -->
<servlet>
<servlet-name>Jersey</servlet-name>
    <servlet-class>
        com.sun.jersey.spi.container.servlet.ServletContainer
    </servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>org.foobar.rest.services;org.codehaus.jackson.jaxrs</param-value>    <!--  use jackson for JSON -->
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>Jersey</servlet-name>
    <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

所需的 Jackson JAR ( http://jackson.codehaus.org/ ) 是:

The required Jackson JARs ( http://jackson.codehaus.org/ ) are:

jackson-core-asl-1.9.10.jar
jackson-core-lgpl-1.9.10.jar
jackson-jaxrs-1.9.10.jar
jackson-mapper-asl-1.9.10.jar
jackson-mapper-lgpl-1.9.10.jar
jackson-mrbean-1.9.10.jar
jackson-smile-1.9.10.jar
jackson-xc-1.9.10.jar