我有一个定义的菜单项，我想在一个页面上两个不同的菜单间的共享。该菜单包含functionallity既菜单之间的相同的，我不希望这两个副本。反正是有在Page.Resources定义菜单项，并引用它在文本菜单下面的XAML？

 ＆LT; Page.Resources＆GT;
    ＆LT;菜单项X：关键=123/＆GT;
＆LT; /Page.Resources>

＆LT;文本菜单＆GT;
    ＆LT;菜单项＆GT;坚硬的东西codeD＆LT; /菜单项＆GT;

    ＆LT;！ - 包括共享菜单这里 - ＆GT;

＆LT; /文本菜单＆GT;
 

解决方案

我通过设定X做到了这一点：在菜单项目本身共享=假。资源是使用它们的默认情况下（这意味着在所有使用一个实例），每个地方之间共享，从而开启了关闭意味着资源的一个新的副本每次制作。

所以：

 ＆LT;菜单项X：关键=myMenuItemX：共享=FALSE/＆GT;
 

您还是会得到它的复制，但是你只需要在一个地方定义它。看看是否有帮助。您可以使用像这样的菜单定义中：

 ＆LT;的StaticResource的ResourceKey =myMenuItem/＆GT;
 

I have a defined MenuItem that I would like to share between two different menus on one page. The menu contains functionallity that is the same between both menus and I do not want two copies of it. Is there anyway to define a MenuItem in the Page.Resources and reference it in the ContextMenu XAML below?

<Page.Resources>
    <MenuItem x:Key="123"/>
</Page.Resources>

<ContextMenu>
    <MenuItem>Something hardcoded</MenuItem>

    <!-- include shared menu here -->

</ContextMenu>

I've done this by setting x:Shared="False" on the menu item itself. Resources are shared between each place that uses them by default (meaning one instance across all uses), so turning that off means that a new "copy" of the resource is made each time.

So:

<MenuItem x:Key="myMenuItem" x:Shared="False" />

You'll still get a "copy" of it, but you only need to define it in one place. See if that helps. You use it like this within your menu definition:

<StaticResource ResourceKey="myMenuItem" />