我要检测android应用呼出。其实我可以检测呼出电话，但它也工作过传入，我不希望出现这种情况。我需要它传出才起作用。这里是我的code ....

 布尔振铃= FALSE;布尔摘机= FALSE;公共无效onCallStateChanged（INT状态，弦乐incomingNumber）{   开关（州）{    案例TelephonyManager.CALL_STATE_IDLE： 如果（（铃声）及！＆安培;摘机）{              ///进来的电话         }          打破;案例TelephonyManager.CALL_STATE_RINGING：    callerPhoneNumber = incomingNumber; Log.d（TAG，振铃）; 振铃= TRUE; 摘机= FALSE; 打破;   案例TelephonyManager.CALL_STATE_OFFHOOK： Log.d（TAG，摘机）; 摘机= TRUE; 振铃= FALSE; 打破;} 

解决方案

您可以写一个广播接收器 android.intent.action.NEW_OUTGOING_CALL 。

看到这里样品code是可用

I want to detect outgoing call in android application . Actually I can detect outgoing calls but it is also working for incoming too and I don't want that. I need it to work only for outgoing. here is my code....

boolean ringing = false;
boolean offhook = false;

public void onCallStateChanged(int state, String incomingNumber) {

   switch (state) {


    case TelephonyManager.CALL_STATE_IDLE:

 if((!ringing)&& offhook){
              ///incomming call
         }
          break;
case TelephonyManager.CALL_STATE_RINGING:

    callerPhoneNumber = incomingNumber;
 Log.d(TAG, "RINGING");
 ringing = true;
 offhook = false;     
 break;

   case TelephonyManager.CALL_STATE_OFFHOOK:

 Log.d(TAG, "OFFHOOK");
 offhook = true;
 ringing = false;
 break;
}

You can write a broadcast receiver for android.intent.action.NEW_OUTGOING_CALL.

See here Sample code is available