我该怎么办使用意图和开发商的名称进行过滤的亚马逊App Store的搜索?亚马逊、我该、意图、开发商

2023-09-06 05:29:55 作者:余生多罪

有没有一种方法来开始烧火的意图,这将导致在AppStore的应用程序打开并显示了一定的开发所有的应用程序?例如,在手机/平板电脑与安装了Android市场,我可以做到这一点:

Is there a way to start an Intent on the Kindle Fire that will cause the AppStore app to open and display all the apps for a certain developer? For instance, on a phone/tablet with the Android Market installed, I can do this:

           Intent otherApps = new Intent(Intent.ACTION_VIEW,Uri.parse("market://search?q=pub:\"" + developerName + "\""));
           activity.startActivity(otherApps);

和展示我在Android Market所有的应用程序。我能做到这一点与亚马逊的App Store?如果是这样,怎么样?我已经试过了意向与其他看似有效的名称(如ZeptoLab),我没有得到任何过滤。这只是我滴在全面未经过滤的应用程序商店。找了一个特定的应用程序,以市场://细节ID = package.name,似乎工作

And show all my apps in the Android Market. Can I do that with the Amazon App Store? If so, how? I've tried that Intent with other seemingly valid names (such as "ZeptoLab") and I don't get any filtering. It just drops me in the full unfiltered App Store. Looking up a specific app with "market://details?id=package.name" does seem to work.

推荐答案

从的https:/ /developer.amazon.com/help/faq.html#Marketing :

要指向您的应用程序用于营销目的使用URL HTTP:/ /www.amazon.com/gp/mas/dl/android?p=packagename (其中包名是你的应用程序包的名字)。

To point to your app for marketing purposes use the URL http://www.amazon.com/gp/mas/dl/android?p=packagename (where packagename is your app package name).

如果你想链接到所有在亚马逊的Appstore应用程序的列表中使用的URL的 http://www.amazon.com/gp/mas/dl/android?p=packagename&showAll=1 。

If you want to link to the list of all your applications on the Amazon Appstore use the URL http://www.amazon.com/gp/mas/dl/android?p=packagename&showAll=1.

例如。 http://www.amazon.com /gp/mas/dl/android?p=com.rovio.angrybirds&showAll=1

这一切都可以在这里看到: https://developer.amazon.com/sdk/in-app-purchasing/sample-$c$c/deeplink.html

All this can be seen here: https://developer.amazon.com/sdk/in-app-purchasing/sample-code/deeplink.html

amzn://apps/android?p=