我读到这（How我做处理浏览器的＆QUOT;分享网页＆QUOT;？意图的Andr​​oid ），我可以得到分享链接检测我的应用程序，现在我怎么活动收到的网址

找到答案：

 意向意图= getIntent（）;
如果（savedInstanceState == NULL和放大器;＆安培;！意图= NULL）{
    Log.d（TAG，意图=空！）;

    如果（intent.getAction（）。等于（Intent.ACTION_SEND））{
        Log.d（TAG。intent.getAction（）等于（Intent.ACTION_SEND））;
        字符串消息= intent.getStringExtra（Intent.EXTRA_TEXT）;
        messageText.setText（消息）;
        receiverText.requestFocus（）;
    }
}
 

解决方案

在您的应用程序收到来自浏览器的分享网页，你也可以得到网页的标题：

 字符串主题= intent.getStringExtra（Intent.EXTRA_SUBJECT）;
 

I read this ( How do I handle the browser's "share page" intent in android? ) which I can get the Share link to detect my app, now how do I get Activity to receive the URL?

Found Answer:

Intent intent = getIntent();
if (savedInstanceState == null && intent != null) {
    Log.d(TAG, "intent != null");

    if (intent.getAction().equals(Intent.ACTION_SEND)) {
        Log.d(TAG, "intent.getAction().equals(Intent.ACTION_SEND)");
        String message = intent.getStringExtra(Intent.EXTRA_TEXT);
        messageText.setText(message);
        receiverText.requestFocus();
    }
}

When your application receives the "Share page" from the browser, you could also get the title of the webpage:

String subject = intent.getStringExtra(Intent.EXTRA_SUBJECT);