我如何开始的意图打开一个Facebook应用程序在手机上，然后导航到prefered页的Facebook？

How can I start an intent to open a Facebook application on a phone and navigate to the prefered page in Facebook?

我想：

Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
intent.putExtra("extra_user_id", "123456789l");
this.startActivity(intent);

好吧，不管我写为1234567891，它总是浏览到我的网页。总是给我，而不是别的。

Well, whatever I write to "1234567891", it is always navigating to my page. Always to me and not else.

我怎么能这样做呢？

推荐答案

我有完全一样的问题，发送的用户ID，但由于某种原因，我的个人资料总是开了朋友的个人资料，而不是。

I had the exactly same problem, sent the user id but for some reason, my profile always opened instead of the friend's profile.

现在的问题是，如果你通过了字符串的龙对象重新$ P $的psents Facebook的UID，甚至长基本类型，其目的将无法稍后阅读。你需要传递一个真实的龙。

The problem is that if you pass the String of the Long object that represents the Facebook UID, or even a long primitive type, the intent won't be able to read it later. You need to pass a real Long.

所以，完整的code是：

So the complete code is:

    Intent intent = new Intent(Intent.ACTION_VIEW);
    intent.setClassName("com.facebook.katana", "com.facebook.katana.ProfileTabHostActivity");
    Long uid = new Long("123456789");
    intent.putExtra("extra_user_id", uid);
    startActivity(intent);

好享受，并希望这会有所帮助： - ）

Ok enjoy and hope this helps :-)

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