我试着写一个应用程序，一个用户可以在Twitter上登录。我用twitter4j像library.My问题是，当我走在页，在这里我必须把用户名和密码，程序块，因为我不知道使用回调排在我的应用程序。有人可以帮我？

公共类MainActivity延伸活动{

 私人微博微博;
RequestToken requestToken;
最终公共静态字符串CALLBACK_SCHEME =X-latify，支持OAuth的Twitter;
最终公共静态字符串CALLBACK_URL = CALLBACK_SCHEME +：//回调;
私人开放的URI;


@覆盖
保护无效的onCreate（包savedInstanceState）{
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.activity_main）;
    按钮B =（按钮）findViewById（R.id.button1）;
    b.setOnClickListener（新View.OnClickListener（）{

        @覆盖
        公共无效的onClick（视图v）{
            新updateTwitterStatus（）执行（）。

        }
    }）;

}

@覆盖
保护无效的onDestroy（）{

    twitter.shutdown（）;
}

类updateTwitterStatus扩展的AsyncTask＆LT;虚空，虚空，字符串＆GT; {

    @覆盖
    保护字符串doInBackground（空... PARAMS）{
        字符串testStatus =PROVA鸣叫;

        ConfigurationBuilder CB =新ConfigurationBuilder（）;

        //设置不accesstoken-桌面客户端以下
        cb.setDebugEnabled（真）
                .setOAuthConsumerKey（******）
                .setOAuthConsumerSecret（
                        *****）;

        尝试 {
            TwitterFactory TF =新TwitterFactory（cb.build（））;
            叽叽喳喳= tf.getInstance（）;
            Log.i（bauu，妙）;

            requestToken = twitter.getOAuthRequestToken（）;
            串authUrl = requestToken.getAuthenticationURL（）;
            startActivity（新意图（Intent.ACTION_VIEW，
                    Uri.parse（requestToken.getAuthenticationURL（））））;
            的uri = Uri.parse（requestToken.getAuthenticationURL（））;

            返回authUrl;

        }赶上（例外五）{
            e.printStackTrace（）;
        }
        返回null;
    }

    @覆盖
    保护无效onPostExecute（String s）将{

        startActivity（新意图（Intent.ACTION_VIEW，Uri.parse（S）））;
    }

}
 

解决方案

请确保在twitter上开发的应用程序选择你的回调网址如下，

 的http：//你的-URL /应用程序：//你的-APP-HOST
 

和在你的Andr​​oid清单文件中的，您可以到Twitter上的actvitiy的， 请确保您定义的：

 ＆LT;意向滤光器＆gt;
            ＆lt;作用机器人：名称=android.intent.action.VIEW/＆GT;
            ＆LT;类机器人：名称=android.intent.category.DEFAULT/＆GT;
            ＆LT;类机器人：名称=android.intent.category.BROWSABLE/＆GT;
            ＆lt;数据
              机器人：主机=YOUR-APP-HOST
              机器人：计划=应用程序/＆GT;
          ＆所述; /意图滤光器＆gt;
 

最后，请确保您的程序，

 最终公共静态字符串CALLBACK_URL =应用程序：//你的-APP-HOST;
 

I try to write an application where an user can log in on twitter. I use twitter4j like library.My problem is that when I go in the page where I must put username and password, the program block because i don't know use callback to came in my application. Someone can me help?

public class MainActivity extends Activity {

private Twitter twitter;
RequestToken requestToken;
final public static String CALLBACK_SCHEME = "x-latify-oauth-twitter";
final public static String CALLBACK_URL = CALLBACK_SCHEME + "://callback";
private Uri uri;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Button b = (Button) findViewById(R.id.button1);
    b.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            new updateTwitterStatus().execute();

        }
    });

}

@Override
protected void onDestroy() {

    twitter.shutdown();
}

class updateTwitterStatus extends AsyncTask<Void, Void, String> {

    @Override
    protected String doInBackground(Void... params) {
        String testStatus = "prova tweet ";

        ConfigurationBuilder cb = new ConfigurationBuilder();

        // the following is set without accesstoken- desktop client
        cb.setDebugEnabled(true)
                .setOAuthConsumerKey("******")
                .setOAuthConsumerSecret(
                        "*****");

        try {
            TwitterFactory tf = new TwitterFactory(cb.build());
            twitter = tf.getInstance();
            Log.i("bauu", "miao");

            requestToken = twitter.getOAuthRequestToken();
            String authUrl = requestToken.getAuthenticationURL();
            startActivity(new Intent(Intent.ACTION_VIEW,
                    Uri.parse(requestToken.getAuthenticationURL())));
            uri = Uri.parse(requestToken.getAuthenticationURL());

            return authUrl;

        } catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String s) {

        startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(s)));    
    }

}

Make sure your callback URL in twitter dev app options are as follows,

http://YOUR-URL/app://YOUR-APP-HOST

and within your android manifest file, in between the of the actvitiy that takes you to twitter, make sure you define:

         <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <data
              android:host="YOUR-APP-HOST"
              android:scheme="app" />
          </intent-filter>

lastly, make sure in your program,

final public static String CALLBACK_URL = "app://YOUR-APP-HOST";