如何获得一个特定的字符串从一个ListView项目字符串、如何获得、项目、ListView
2023-09-05 10:20:43
作者：国产平胸女
我想做什么
您好，大家好，我创建一个应用程序为我的朋友，我只是表明他的渠道在我的应用程序。我得到的视频的数据在JSON。
现在我发现了一个问题。当我填写的数据为我的ListView在SimpleListAdapter，并设法得到它通过一个OnItemClickListner和检索他们交给 lv.getItemAtPosition（位置）; 我得到这是所有的数据存储在具体的行。但我只需要链接/ URL我保存在该领域。
问题
就像你读我得到了我的ListView一个以上的信息是完全有四根弦（拇指，标题，内容，链接）。但我只需要获得链接的字符串，我怎么能做到这一点，在这儿你找到code。
code
test2.java
包de.stepforward;
进口java.io.BufferedReader中;
进口java.io.FileOutputStream中;
进口的java.io.InputStream;
进口java.io.InputStreamReader中;
进口java.io.OutputStream中;
进口java.net.MalformedURLException;
进口的java.net.URL;
进口java.net.URLConnection中;
进口的java.util.ArrayList;
进口的java.util.HashMap;
进口的java.util.List;
进口的java.util.Map;
进口org.apache.http.NameValuePair;
进口org.json.JSONArray;
进口org.json.JSONObject;
进口android.app.ListActivity;
进口android.database.Cursor;
进口android.media.RingtoneManager;
进口android.os.Bundle;
进口android.util.Log;
进口android.view.View;
进口android.widget.AdapterView.OnItemClickListener;
进口android.widget.AdapterView;
进口android.widget.ListAdapter;
进口android.widget.ListView;
进口android.widget.SimpleAdapter;
进口android.widget.SimpleCursorAdapter;
进口android.widget.TextView;
进口android.widget.Toast;
公共类test2的扩展ListActivity {
@覆盖
公共无效的onCreate（包savedInstanceState）{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.main）;
字符串结果=;
串线= NULL;
ArrayList的＆LT; HashMap的＆LT;字符串，字符串＆GT;＆GT; mylist中=新的ArrayList＆LT; HashMap的＆LT;字符串，字符串＆GT;＆GT;（）;
//从以下网址获取数据
尝试{
网址URL =新的URL（http://gdata.youtube.com/feeds/mobile/users/TheStepForward/uploads?alt=json&format=1）;
URLConnection的康恩= url.openConnection（）;
StringBuilder的SB =新的StringBuilder（）;
的BufferedReader RD =新的BufferedReader（新的InputStreamReader（conn.getInputStream（）））;
//读取D响应，直到D结束
而（（行= rd.readLine（））！= NULL）{
sb.append（行+\ N）;
}
结果= sb.toString（）;
Log.v（log_tag，追加字符串+结果）;
}赶上（例外五）{
Log.e（log_tag，错误转换结果+ e.toString（））;
}
尝试{
JSONObject的JSON =新的JSONObject的（结果）;
JSONObject的饲料= json.getJSONObject（饲料）;
JSONArray entrylist = feed.getJSONArray（输入）;
的for（int i = 0; I＆LT; entrylist.length（）;我++）{
//获取标题
的JSONObject电影= entrylist.getJSONObject（ⅰ）;
JSONObject的标题= movie.getJSONObject（标题）;
字符串txtTitle = title.getString（$ T）;
Log.d（标题，txtTitle）;
//获取描述
JSONObject的内容= movie.getJSONObject（内容）;
字符串txtContent = content.getString（$ T）;
Log.d（内容，txtContent）;
//获取链接
JSONArray链表= movie.getJSONArray（链接）;
的JSONObject链路= linklist.getJSONObject（0）;
字符串txtLink = link.getString（HREF）;
Log.d（链接，txtLink）;
//获取缩略图
JSONObject的medialist中= movie.getJSONObject（传媒$集团）;
JSONArray thumblist = medialist.getJSONArray（媒体$缩略图）;
JSONObject的拇指= thumblist.getJSONObject（2）;
字符串txtThumb = thumb.getString（URL）;
Log.d（拇指，txtThumb.toString（））;
//字符串数组daraus中的Hashmapfüllen玛沁UND
HashMap的＆LT;字符串，字符串＆GT;图=新的HashMap＆LT;字符串，字符串＆GT;（）;
map.put（拇指，txtThumb）;
map.put（标题，txtTitle）;
map.put（内容，txtContent）;
map.put（链接，txtLink）;
mylist.add（图）
}
// ListView的füllen
ListAdapter适配器=新SimpleAdapter（这一点，mylist中，R.layout.lit，
新的String [] {拇指，标题，内容，链接}，
新的INT [] {R.id.img_video，R.id.txt_title，R.id.txt_subtitle}）;
setListAdapter（适配器）;
// OnClickLister UM的Youtube视频祖öffnen
最终的ListView LV = getListView（）;
lv.setOnItemClickListener（新OnItemClickListener（）{
公共无效onItemClick（适配器视图＆LT;＆GT;母公司，视图V，INT位置，长的id）{
lv.getItemAtPosition（位置）;
}
}）;
}赶上（例外五）{
Log.e（log_tag，错误转换结果+ e.toString（））;
}
}
}
感谢你在前进
解决方案 最终的ListView LV = getListView（）;
lv.setOnItemClickListener（新OnItemClickListener（）{
公共无效onItemClick（适配器视图＆LT;＆GT;母公司，视图V，INT位置，长的id）{
地图＆LT;字符串，字符串＆GT;地图= mylist.get（位置）;
字符串link = map.get（链接）;
}
}）;
What I'm trying to do
Hello Guys, I'm creating an App for a friend of mine, i simply show his Channel in my App. I get the Data of the Videos over JSON.
Now I found a Problem. When I filled the data into my ListView over the SimpleListAdapter and try to get it over an OnItemClickListner and retrieve them over lv.getItemAtPosition(position); I get all data which is stored in the specific row. But I only need the Link/Url I saved in that field.
Question
Like you read I got more than one information in my ListView to be exactly there are four Strings (Thumb,Title, Content, Link). But I only need to get the String of the Link, how can I do this, down here you find the Code.
Code
test2.java
package de.stepforward;
import java.io.BufferedReader;
import java.io.FileOutputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import org.apache.http.NameValuePair;
import org.json.JSONArray;
import org.json.JSONObject;
import android.app.ListActivity;
import android.database.Cursor;
import android.media.RingtoneManager;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.AdapterView;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.SimpleCursorAdapter;
import android.widget.TextView;
import android.widget.Toast;
public class test2 extends ListActivity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
String result = "";
String line = null;
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
//get the Data from URL
try{
URL url = new URL("http://gdata.youtube.com/feeds/mobile/users/TheStepForward/uploads?alt=json&format=1");
URLConnection conn = url.openConnection();
StringBuilder sb = new StringBuilder();
BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
//read d response till d end
while ((line = rd.readLine()) != null) {
sb.append(line + "\n");
}
result = sb.toString();
Log.v("log_tag", "Append String " + result);
} catch (Exception e) {
Log.e("log_tag", "Error converting result " + e.toString());
}
try{
JSONObject json = new JSONObject(result);
JSONObject feed = json.getJSONObject("feed");
JSONArray entrylist = feed.getJSONArray("entry");
for(int i=0;i<entrylist.length();i++){
//Get Title
JSONObject movie = entrylist.getJSONObject(i);
JSONObject title = movie.getJSONObject("title");
String txtTitle = title.getString("$t");
Log.d("Title", txtTitle);
//Get Description
JSONObject content = movie.getJSONObject("content");
String txtContent = content.getString("$t");
Log.d("Content", txtContent);
//Get Link
JSONArray linklist = movie.getJSONArray("link");
JSONObject link = linklist.getJSONObject(0);
String txtLink = link.getString("href");
Log.d("Link", txtLink);
//Get Thumbnail
JSONObject medialist = movie.getJSONObject("media$group");
JSONArray thumblist = medialist.getJSONArray("media$thumbnail");
JSONObject thumb = thumblist.getJSONObject(2);
String txtThumb = thumb.getString("url");
Log.d("Thumb", txtThumb.toString());
//String Array daraus machen und in Hashmap füllen
HashMap<String, String> map = new HashMap<String, String>();
map.put("Thumb", txtThumb);
map.put("Title", txtTitle);
map.put("Content", txtContent);
map.put("Link", txtLink);
mylist.add(map);
}
//ListView füllen
ListAdapter adapter = new SimpleAdapter(this, mylist , R.layout.lit,
new String[] { "Thumb","Title","Content","Link"},
new int[] { R.id.img_video,R.id.txt_title,R.id.txt_subtitle});
setListAdapter(adapter);
//OnClickLister um Youtube-Video zu öffnen
final ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener(){
public void onItemClick(AdapterView<?> parent, View v, int position, long id) {
lv.getItemAtPosition(position);
}
});
}catch (Exception e) {
Log.e("log_tag", "Error converting result " + e.toString());
}
}
}
Thank you in Advance
解决方案 final ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener(){
public void onItemClick(AdapterView<?> parent, View v, int position, long id) {
Map<String, String> map = mylist.get(position);
String link = map.get("Link");
}
});
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