上传的MS Word文件从机器人到.NET WCF？人到、机器、上传、文件
2023-09-05 09:27:40
作者：别惹菇凉
我在从我的Android应用程序上传doc文件到.NET WCF的问题。我能够发送文件，但它不支持WCF结束。 下面是我的方法上传：
保护无效checkinmethod（字符串RID）抛出异常{
文件SDCardRoot = Environment.getExternalStorageDirectory（）;
//创建一个新的文件，指定路径和文件名
//这是我们要保存的文件。
档案文件=新的文件（SDCardRoot，摆脱+DOC）;
InputStream的时间=新的FileInputStream（文件）;
byte []的字节组=新的字节[（INT）file.length（）];
INT AB = 0;
做
{
AB = in.read（字节数组，0，bytearray.length）;
}而（AB大于0）;
InputStream的mystream =新ByteArrayInputStream的（字节组）;
InputStreamEntity SE =新InputStreamEntity（mystream，10000）;
HttpPost请求=新HttpPost（http://10.66.52.247/tutorwcf/Service.svc/Service/updateMyDoc1）;
request.setHeader（接受，应用/ JSON）;
request.setHeader（内容型，应用程序/ MSWORD）;
request.setEntity（SE）;
尝试 {
DefaultHttpClient的HttpClient =新DefaultHttpClient（）;
HTT presponse响应= httpClient.execute（要求）;
HttpEntity responseEntity = response.getEntity（）;
//读取响应数据到缓冲区
的char []缓冲区=新的char [（INT）responseEntity.getContentLength（）];
InputStream的流= responseEntity.getContent（）;
InputStreamReader的读者=新的InputStreamReader（流）;
reader.read（缓冲液）;
stream.close（）;
statuss.setText（新的字符串（缓冲））;
//
}
赶上（例外五）{
// TODO：处理异常
Log.e（喜，例外，E）;
statuss.setText（异常）;
}
}
下面是.NET code：
的FileStream fileToupload =新的FileStream（D：\\ myfile.doc，FileMode.Create，FileAccess.Write）;
byte []的字节组=新的字节[10000]
INT读取动作，totalBytesRead = 0;
做
{
读取动作= mystream.Read（字节数组，0，bytearray.Length）;
totalBytesRead + =读取动作;
}而（读取动作大于0）;
fileToupload.Write（字节数组，0，bytearray.Length）;
fileToupload.Close（）;
fileToupload.Dispose（）;
返回成功;
}
请发送链接或code或任何东西。
如果你没有知道关于这个请排列了这个问题.. 谢谢
解决方案 公共无效checkinstream（RID字符串，字符串文件名）抛出IOException异常
{
网址URL = NULL;
HttpURLConnection的康恩= NULL;
DataOutputStream类DOS = NULL;
inStream中的DataInputStream = NULL;
字符串existingFileName = NULL;
existingFileName =/mnt/sdcard/"+rid+".doc;
INT读取动作，方bytesAvailable，缓冲区大小;
byte []的缓冲区;
INT maxBufferSize = Integer.MAX_VALUE的;
字符串responseFromServer =;
URL =新的URL（http://10.66.51.241/mywcf/Service.svc/Service/uploadMyDoc）;
尝试
{
// ------------------客户端请求
的FileInputStream的FileInputStream =新的FileInputStream（新文件（existingFileName））;
//打开一个HTTP连接网址
康恩=（HttpURLConnection类）url.openConnection（）;
//允许输入
conn.setDoInput（真正的）;
//允许输出
conn.setDoOutput（真正的）;
//不要使用缓存副本。
conn.setUseCaches（假）;
//使用POST方法。
conn.setRequestMethod（POST）;
conn.setRequestProperty（连接，保持活动）;
conn.setRequestProperty（内容类型，应用程序/流）;
DOS =新DataOutputStream类（conn.getOutputStream（））;
// dos.writeBytes（twoHyphens +边界+ lineEnd）;
//dos.writeBytes("Content-Disposition：表格数据;名称= \UploadedFile的\;文件名= \+ existingFileName +\+ lineEnd）;
// dos.writeBytes（lineEnd）;
//创建最大大小的缓冲区
方bytesAvailable = fileInputStream.available（）;
BUFFERSIZE = Math.min（方bytesAvailable，maxBufferSize）;
缓冲区=新的字节[BUFFERSIZE]
//读取文件，并将其写入形式...
读取动作= fileInputStream.read（缓冲液，0，BUFFERSIZE）;
而（读取动作大于0）
{
dos.write（缓冲液，0，BUFFERSIZE）;
方bytesAvailable = fileInputStream.available（）;
BUFFERSIZE = Math.min（方bytesAvailable，maxBufferSize）;
读取动作= fileInputStream.read（缓冲液，0，BUFFERSIZE）;
}
//发送多部分表格数据文件数据后necesssary ...
dos.writeBytes（lineEnd）;
//关闭流
Log.e（调试，twoHyphens +边界+ twoHyphens + lineEnd）;
fileInputStream.close（）;
dos.flush（）;
dos.close（）;
}
赶上（MalformedURLException的前）
{
Log.e（调试，错误：+ ex.getMessage（），前）;
}
赶上（IOException异常IOE）
{
Log.e（调试，错误：+ ioe.getMessage（），IOE）;
}
// ------------------读取服务器响应
尝试 {
inStream中=新的DataInputStream（conn.getInputStream（））;
字符串str;
而（（海峡= inStream.readLine（））！= NULL）
{
Log.e（调试，服务器响应+ STR）;
statuss.setText（STR）;
}
inStream.close（）;
}
赶上（IOException异常ioex）{
Log.e（调试，错误：+ ioex.getMessage（），ioex）;
}
}
在.NET端创建一个接收流的WCF方法。 谢谢。
I have problem in uploading .doc file to .Net WCF from my Android app. I am able to send file but it is not supported on WCF end. Here is my method for uploading:
protected void checkinmethod(String rid) throws Exception {
File SDCardRoot = Environment.getExternalStorageDirectory();
//create a new file, specifying the path, and the filename
//which we want to save the file as.
File file = new File(SDCardRoot, rid+".doc");
InputStream in = new FileInputStream(file);
byte[] bytearray=new byte[(int) file.length()];
int ab=0;
do
{
ab=in.read(bytearray, 0, bytearray.length);
} while(ab>0);
InputStream mystream= new ByteArrayInputStream(bytearray);
InputStreamEntity se=new InputStreamEntity(mystream, 10000);
HttpPost request = new HttpPost("http://10.66.52.247/tutorwcf/Service.svc/Service/updateMyDoc1");
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/msword");
request.setEntity(se);
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(request);
HttpEntity responseEntity = response.getEntity();
// Read response data into buffer
char[] buffer = new char[(int)responseEntity.getContentLength()];
InputStream stream = responseEntity.getContent();
InputStreamReader reader = new InputStreamReader(stream);
reader.read(buffer);
stream.close();
statuss.setText(new String(buffer));
//
}
catch (Exception e) {
// TODO: handle exception
Log.e("hi", "exception is", e);
statuss.setText("exception");
}
}
here is .net code:
FileStream fileToupload = new FileStream("D:\\myfile.doc", FileMode.Create, FileAccess.Write);
byte[] bytearray = new byte[10000];
int bytesRead, totalBytesRead = 0;
do
{
bytesRead = mystream.Read(bytearray, 0, bytearray.Length);
totalBytesRead += bytesRead;
} while (bytesRead > 0);
fileToupload.Write(bytearray, 0, bytearray.Length);
fileToupload.Close();
fileToupload.Dispose();
return "success";
}
Please send links or code or any thing.
If you don't have idea about this please rank up this question.. thanks
解决方案public void checkinstream(String rid, String filename ) throws IOException
{
URL url=null;
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName= null;
existingFileName= "/mnt/sdcard/"+rid+".doc";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = Integer.MAX_VALUE;
String responseFromServer = "";
url = new URL("http://10.66.51.241/mywcf/Service.svc/Service/uploadMyDoc");
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "application/stream");
dos = new DataOutputStream( conn.getOutputStream() );
// dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
// dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
// close streams
Log.e("Debug",twoHyphens + boundary + twoHyphens + lineEnd);
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
statuss.setText(str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
On the .net end create a wcf method which receives stream. Thanks.
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