我需要写一个shell脚本来启动和停止的机器人服务。

I need to write a shell script to start and stop an android service .

推荐答案

我在Android的初学者，但得到它的工作是这样的：

I'm a beginner in Android, but got it working like this:

在AndroidManifest.xml中，请确保您，在＆lt;应用＆GT; ，有这样的事情：

in AndroidManifest.xml, make sure you, inside <application>, have something like this:

<service android:name="com.some.package.name.YourServiceSubClassName" android:permission="com.some.package.name.YourServiceSubClassName">
    <intent-filter>
        <action android:name="com.some.package.name.YourServiceSubClassName"/>
    </intent-filter>
</service>

其中， YourServiceSubClassName 延长 android.app.Service 是Java类的服务。其中， com.some.package 是软件包名，对我来说无论是在AndroidManifest.xml中，并在Java中。 二手一个javabeat.net文章的帮助下，寻找＆LT;服务＆GT;

where YourServiceSubClassName extend android.app.Service is your java class that is the service. Where com.some.package is the package name, for me both in AndroidManifest.xml and in Java. Used a javabeat.net article as help, look for <service>

另请注意，所谓的包名和类名之间应该有。服务。的文字，我想这是一些约定，但对我来说这引起 ClassNotFoundException的是我还没有解决。

Note also, supposedly between the package name and the class name there should be .service. in the text, I guess this is some convention, but for me this caused ClassNotFoundException that I'm yet to solve.

然后，安装APK。我从Eclipse中没有，但也 ADB安装-r yourApkHere.apk 应该工作。卸载是亚行卸载com.some.package.name ，顺便说一句。

Then, install your apk. I did from eclipse but also adb install -r yourApkHere.apk should work. Uninstall is adb uninstall com.some.package.name, btw.

您可以开始从主机系统就是这样，感谢只是添和< A HREF =htt​​p://stackoverflow.com/a/8469325/611007> MrRoy ：

You can start it from host system like this, thanks Just a Tim and MrRoy:

adb shell am startservice com.some.package.name/.YourServiceSubClassName

有趣的是，我并不需要 -n 。

要停止，我用

adb shell am force-stop com.some.package.name

希望它帮助。

Hope it helps.

由于我是个初学者，请随时孚瑞特编辑/评论修复任何误解​​（如：可能关于。服务的组件。（？）的名字）

As I'm a beginner, please feel freet to edit/comment to fix any misconceptions (eg. probably regarding .service. in the component (?) name).