执行POST从Android的一个日期时间到WCF REST风格的JSON服务风格、日期、时间、POST

2023-09-05 04:57:13 作者:对爱情过敏

研究小时后,我还没有找到任何答案。 我试图发送一个DateTime作为参数传递给暴露了一个WCF RESTful服务使用JSON编码的一个方法。 请求是这样的:

after hours of research I still haven't found any answer. I'm trying to send a DateTime as a Parameter to a Method exposed over a WCF RESTful Service with JSON encoding. The request looks like this:

POST http://IP:PORT/LogService/json/GetLogEntriesByModule HTTP/1.1
Content-Length: 100
Content-Type: application/json
Host: IP:PORT
Connection: Keep-Alive
User-Agent: Apache-HttpClient/UNAVAILABLE (java 1.4)
Expect: 100-Continue

{"maxentries":10,"upperdate":"1280703601462","lowerdate":"1277938801462","module":"Windows Service"}

我尝试了几种格式的日期时间:

I tried several formats for the DateTime:

2010-07-01T10:54:00 在其发送的WCFTestClient应用过的net.tcp连带结果...... 2010-07-01T10:54:00 which is send by the WCFTestClient Application over net.tcp and it gets results...

在Methoddefinition:

The Methoddefinition:

LogEntry[] GetLogEntriesByModule(
 string module,
 DateTime lowerDate,
 DateTime upperDate,
 int maxEntries,
 out bool maxEntriesReached
)

我总是以下响应:

I always the the following response:

HTTP/1.1 200 OK
Content-Length: 60
Content-Type: application/json; charset=utf-8
Server: Microsoft-HTTPAPI/2.0
Date: Fri, 02 Jul 2010 09:07:04 GMT

{"GetLogEntriesByModuleResult":[],"maxEntriesReached":false}

看来日期时间不正确地分析,因为有几个条目在​​日志中时间...

It seems the DateTime isn't correctly parsed, because there are several Entries in the Log for that Time...

有谁知道如何做到这一点?

Does anyone know on how to do this?

编辑:存在的问题是在服务器侧和已经解决

The Problem was on the server side and has been resolved.

推荐答案

有关使用发布日期WCF服务的正确的格式: /日期(532.44亿)/ 凡在barckets的数量是毫秒自1970年以来UTC午夜数。

The correct format for posting dates to WCF service is using : "/Date(53244000000)/" where the number in barckets is the number of milliseconds since 1970 UTC Midnight.

Date dt = new Date();
long date = Date.UTC(dt.getYear(), dt.getMonth(), dt.getDay(), dt.getHours(),dt.getMinutes(), dt.getSeconds());
String senddate = "/date("+date+")/";

,然后用它作为以下

And then use it as below

inputparam.put("DateTime", datetime);

这将工作的肯定......请,如果您有任何问题,分享。

This will work for sure... Please share if you have any issues.

 
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