有什么办法中显示类似名称  TechCrunch的 蠢 美国航空航天局 在列表视图，当用户点击其中一个，就应该打开的链接，相应的上市网站的意图。

Is there any way in to Show Names like "TechCrunch" "Twit" "NASA" in the listview and when the user clicks on one of them , it should open an intent with the link for corresponding Websites listed.

任何想法AP preciated。

Any ideas appreciated.

推荐答案

如果您不希望的ListView 是由数据库生成的，你要添加的每个网站上的的ListView的适配器自己，那么你可以做到以下几点。

If you don't want the ListView to be generated by a database and you want to add every website to the adapter of your ListView yourself, then you can do the following.

您需要创建一个项目类，如下所示：

You would have to create an Item class, that looks like this:

public class Item {

    private String mName;
    private int mLink;

    public Item(String name, int link) {

        this.mName = name;
        this.mLink = link;
    }

    public int getLink() {

        return mLink;
    }

    public void setLink(int link) {

        this.mLink = link;
    }

    public String getName() {

        return mName;
    }

    public void setName(String name) {

        this.mName = name;
    }

    @Override
    public String toString() {

        return this.mName;
    }
}

，然后设置你的ListView的适配器是这样的：

and then set the adapter of your ListView like this:

List<Item> dataForTheAdapter = new ArrayList<Item>();

// add some data
dataForTheAdapter.add(new Item("Apple", "www.Apple.com"));
dataForTheAdapter.add(new Item("Microsoft", "www.Microsoft.com"));
dataForTheAdapter.add(new Item("Google", "www.Google.com"));

mContext = MyActivity.this;
// R.layout.row is a layout, that contains only one TextView
mAdapter = new ArrayAdapter<Item>(mContext, R.layout.row, dataForTheAdapter);

ListView listView = (ListView) findViewById(R.id.listView);
listView.setAdapter(mAdapter);

现在设置 OnItemClickListener 您的ListView 。

listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {

    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

        String url = mAdapter.getItem(position).getLink();
        Intent i = new Intent(Intent.ACTION_VIEW);
        i.setData(Uri.parse(url));
        startActivity(i);
    }
});