从maps.google.com方向Android开时间方向、时间、google、maps
2023-09-05 01:21:05
作者：旧人不覆°
目前，我用这code，从一个地址到另一个询问谷歌地图的方向，然后，我只是画它从它的GeometryCollection一个图形页面。但是，这还不够我也需要提取的KML预计总工期。有人可以给一个小样本code来帮助我？谢谢
StringBuilder的urlString =新的StringBuilder（）;
urlString.append（http://maps.google.com/maps?f=d&hl=en）;
urlString.append（＆放大器; SADDR =）; //从
urlString.append（Double.toString（（双）src.getLatitudeE6（）/ 1.0E6））;
urlString.append（，）;
urlString.append（Double.toString（（双）src.getLongitudeE6（）/ 1.0E6））;
urlString.append（＆放大器; DADDR =）; //给
urlString.append（Double.toString（（双）dest.getLatitudeE6（）/ 1.0E6））;
urlString.append（，）;
urlString.append（Double.toString（（双）dest.getLongitudeE6（）/ 1.0E6））;
urlString.append（＆放大器，即= UTF8＆功放; 0安培; OM = 0＆放大器;输出= KML）;
//Log.d("xxx，URL =+ urlString.toString（））;
//获取KML（XML）文档。并解析它来获得坐标（方向线）。
文档DOC = NULL;
HttpURLConnection类的URLConnection = NULL;
网址URL = NULL;
尝试
{
URL =新的URL（urlString.toString（））;
的URLConnection =（HttpURLConnection类）url.openConnection（）;
urlConnection.setRequestMethod（GET）;
urlConnection.setDoOutput（真正的）;
urlConnection.setDoInput（真正的）;
urlConnection.connect（）;
DBF = DocumentBuilderFactory.newInstance（）;
DB = dbf.newDocumentBuilder（）;
文档= db.parse（urlConnection.getInputStream（））;
如果（doc.getElementsByTagName（GeometryCollection的）的getLength（）＆GT; 0）
{
//字符串路径= doc.getElementsByTagName("GeometryCollection").item(0).getFirstChild().getFirstChild().getNodeName();
字符串路径= doc.getElementsByTagName("GeometryCollection").item(0).getFirstChild().getFirstChild().getFirstChild().getNodeValue() ;
//Log.d("xxx","path="+路径）;
的String []对= path.split（）;
串[] lngLat =双[0] .split（，）; // lngLat [0] =经度lngLat [1] =纬度lngLat [2] =高度
// SRC
的GeoPoint startGP =新的GeoPoint（（int）的（Double.parseDouble（lngLat [1]）* 1E6），（int）的（Double.parseDouble（lngLat [0]）* 1E6））;
。mMapView01.getOverlays（）增加（新MyOverLay（startGP，startGP，1））;
的GeoPoint GP1;
的GeoPoint GP2 = startGP;
的for（int i = 1; I＆LT; pairs.length;我++）//最后一个会崩溃
{
lngLat =对[I] .split（，）;
GP1 = GP2;
// 小心！对于GeoPoint对象，第一：纬度，第二：经度
GP2 =新的GeoPoint（（int）的（Double.parseDouble（lngLat [1]）* 1E6），（int）的（Double.parseDouble（lngLat [0]）* 1E6））;
。mMapView01.getOverlays（）增加（新MyOverLay（GP1，gp2,2，颜色））;
//Log.d("xxx","pair：+对[I]）;
}
。mMapView01.getOverlays（）增加（新MyOverLay（DEST，DEST，3））; //使用默认颜色
}
}赶上（MalformedURLException异常E）{
e.printStackTrace（）;
}赶上（IOException异常E）{
e.printStackTrace（）;
}赶上（的SAXException E）{
e.printStackTrace（）;
}赶上（的ParserConfigurationException E）{
e.printStackTrace（）;
}
}
解决方案
使用新的路线 API。持续时间在响应中返回和KML，我认为断谷歌地图许可证条款反正不多解析。
更新。确定使用JSON输出，它解析内置了Android系统。
前网址
响应是
{
状态：OK，
路线：[{
摘要：I-40 W，
腿：[{
脚步： [ {
travel_mode：驾驶，
START_LOCATION：{
纬度：41.8507300，
液化天然气：-87.6512600
}，
END_LOCATION：{
纬度：41.8525800，
液化天然气：-87.6514100
}，
折线：{
点：一〜L〜FJK〜uOwHJy @ P，
层次：B B？
}，
持续时间：{
值：19，
文：1分钟
}，
html_instructions：头\ u003cb \ u003enorth \ u003c / B \上\ u003cb \ u003eS摩根圣\ u003c / B \ u003e对\ u003cb \ u003eW塞马克路\ u003c / B \ u003e u003e
距离： {
值：207，
文：0.1英里
}
}，
...
...额外的步骤这个腿
...
......这条路线的附加腿
持续时间：{
值：74384，
文：20.小时40分钟
}，
距离： {
值：2137146，
文：1328 MI
}，
START_LOCATION：{
纬度：35.4675602，
液化天然气：-97.5164276
}，
END_LOCATION：{
纬度：34.0522342，
液化天然气：-118.2436849
}，
START_ADDRESS：俄克拉何马城，OK，USA，
end_address：洛杉矶，加利福尼亚，美国
}]，
版权：地图数据©2010谷歌，桑伯恩
overview_polyline：{
点： "a~l~Fjk~uOnzh@vlbBtc~@tsE`vnApw{A`dw@~w\\|tNtqf@l{Yd_Fblh@rxo@b}@xxSfytAblk@xxaBeJxlcBb~t@zbh@jc|Bx}C`rv@rw|@rlhA~dVzeo@vrSnc}Axf]fjz@xfFbw~@dz{A~d{A|zOxbrBbdUvpo@`cFp~xBc`Hk@nurDznmFfwMbwz@bbl@lq~@loPpxq@bw_@v|{CbtY~jGqeMb{iF|n\\~mbDzeVh_Wr|Efc\\x`Ij{kE}mAb~uF{cNd}xBjp]fulBiwJpgg@|kHntyArpb@bijCk_Kv~eGyqTj_|@`uV`k|DcsNdwxAott@r}q@_gc@nu`CnvHx`k@dse@j|p@zpiAp|gEicy@`omFvaErfo@igQxnlApqGze~AsyRzrjAb__@ftyB}pIlo_BflmA~yQftNboWzoAlzp@mz`@|}_@fda@jakEitAn{fB_a]lexClshBtmqAdmY_hLxiZd~XtaBndgC",
层次：BBBAAAAABAABAAAAAABBAAABBAAAABBAAABABAAABABBAABAABAAAABABABABBABAABB
}，
警告：[]，
waypoint_order：[0，1]
}]
}
让我们假设你使用标准的HTTP客户端库，现在有一个字符串的响应。
的JSONObject的JSONObject =新的JSONObject（响应）; //解析响应成JSON对象
JSONObject的routeObject = jsonObject.getJSONObject（路线）; //拉出路线对象
JSONObject的durationObject = jsonObject.getJSONObject（期限）; //拉出持续时间对象
字符串长度= durationObject.getString（文字）; //这应该是持续时间文本值（20小时40分钟）
您将不得不将所有在一个try-catch块捕获 JSONExceptions 。
At the moment I am using this code to inquire google maps for directions from an address to another one, then I simply draw it on a mapview from its GeometryCollection. But yet this isn't enough I need also to extract the total expected duration from the kml. can someone give a little sample code to help me? thanks
StringBuilder urlString = new StringBuilder();
urlString.append("http://maps.google.com/maps?f=d&hl=en");
urlString.append("&saddr=");//from
urlString.append( Double.toString((double)src.getLatitudeE6()/1.0E6 ));
urlString.append(",");
urlString.append( Double.toString((double)src.getLongitudeE6()/1.0E6 ));
urlString.append("&daddr=");//to
urlString.append( Double.toString((double)dest.getLatitudeE6()/1.0E6 ));
urlString.append(",");
urlString.append( Double.toString((double)dest.getLongitudeE6()/1.0E6 ));
urlString.append("&ie=UTF8&0&om=0&output=kml");
//Log.d("xxx","URL="+urlString.toString());
// get the kml (XML) doc. And parse it to get the coordinates(direction route).
Document doc = null;
HttpURLConnection urlConnection= null;
URL url = null;
try
{
url = new URL(urlString.toString());
urlConnection=(HttpURLConnection)url.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.setDoOutput(true);
urlConnection.setDoInput(true);
urlConnection.connect();
dbf = DocumentBuilderFactory.newInstance();
db = dbf.newDocumentBuilder();
doc = db.parse(urlConnection.getInputStream());
if(doc.getElementsByTagName("GeometryCollection").getLength()>0)
{
//String path = doc.getElementsByTagName("GeometryCollection").item(0).getFirstChild().getFirstChild().getNodeName();
String path = doc.getElementsByTagName("GeometryCollection").item(0).getFirstChild().getFirstChild().getFirstChild().getNodeValue() ;
//Log.d("xxx","path="+ path);
String[] pairs = path.split(" ");
String[] lngLat = pairs[0].split(","); // lngLat[0]=longitude lngLat[1]=latitude lngLat[2]=height
// src
GeoPoint startGP = new GeoPoint((int)(Double.parseDouble(lngLat[1])*1E6),(int)(Double.parseDouble(lngLat[0])*1E6));
mMapView01.getOverlays().add(new MyOverLay(startGP,startGP,1));
GeoPoint gp1;
GeoPoint gp2 = startGP;
for(int i=1;i<pairs.length;i++) // the last one would be crash
{
lngLat = pairs[i].split(",");
gp1 = gp2;
// watch out! For GeoPoint, first:latitude, second:longitude
gp2 = new GeoPoint((int)(Double.parseDouble(lngLat[1])*1E6),(int)(Double.parseDouble(lngLat[0])*1E6));
mMapView01.getOverlays().add(new MyOverLay(gp1,gp2,2,color));
//Log.d("xxx","pair:" + pairs[i]);
}
mMapView01.getOverlays().add(new MyOverLay(dest,dest, 3)); // use the default color
}
}catch (MalformedURLException e){
e.printStackTrace();
}catch (IOException e){
e.printStackTrace();
}catch (SAXException e){
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
}
}
解决方案
Use the new Directions api. The duration is returned in the response and no more parsing of KML, which I think breaks the Google maps license terms anyways.
Update. Ok use the JSON output, with it parsing is built into Android.
Ex url
Response is
{
"status": "OK",
"routes": [ {
"summary": "I-40 W",
"legs": [ {
"steps": [ {
"travel_mode": "DRIVING",
"start_location": {
"lat": 41.8507300,
"lng": -87.6512600
},
"end_location": {
"lat": 41.8525800,
"lng": -87.6514100
},
"polyline": {
"points": "a~l~Fjk~uOwHJy@P",
"levels": "B?B"
},
"duration": {
"value": 19,
"text": "1 min"
},
"html_instructions": "Head \u003cb\u003enorth\u003c/b\u003e on \u003cb\u003eS Morgan St\u003c/b\u003e toward \u003cb\u003eW Cermak Rd\u003c/b\u003e",
"distance": {
"value": 207,
"text": "0.1 mi"
}
},
...
... additional steps of this leg
...
... additional legs of this route
"duration": {
"value": 74384,
"text": "20 hours 40 mins"
},
"distance": {
"value": 2137146,
"text": "1,328 mi"
},
"start_location": {
"lat": 35.4675602,
"lng": -97.5164276
},
"end_location": {
"lat": 34.0522342,
"lng": -118.2436849
},
"start_address": "Oklahoma City, OK, USA",
"end_address": "Los Angeles, CA, USA"
} ],
"copyrights": "Map data ©2010 Google, Sanborn",
"overview_polyline": {
"points": "a~l~Fjk~uOnzh@vlbBtc~@tsE`vnApw{A`dw@~w\\|tNtqf@l{Yd_Fblh@rxo@b}@xxSfytAblk@xxaBeJxlcBb~t@zbh@jc|Bx}C`rv@rw|@rlhA~dVzeo@vrSnc}Axf]fjz@xfFbw~@dz{A~d{A|zOxbrBbdUvpo@`cFp~xBc`Hk@nurDznmFfwMbwz@bbl@lq~@loPpxq@bw_@v|{CbtY~jGqeMb{iF|n\\~mbDzeVh_Wr|Efc\\x`Ij{kE}mAb~uF{cNd}xBjp]fulBiwJpgg@|kHntyArpb@bijCk_Kv~eGyqTj_|@`uV`k|DcsNdwxAott@r}q@_gc@nu`CnvHx`k@dse@j|p@zpiAp|gEicy@`omFvaErfo@igQxnlApqGze~AsyRzrjAb__@ftyB}pIlo_BflmA~yQftNboWzoAlzp@mz`@|}_@fda@jakEitAn{fB_a]lexClshBtmqAdmY_hLxiZd~XtaBndgC",
"levels": "BBBAAAAABAABAAAAAABBAAABBAAAABBAAABABAAABABBAABAABAAAABABABABBABAABB"
},
"warnings": [ ],
"waypoint_order": [ 0, 1 ]
} ]
}
Let's say you used the standard http client libraries and now have the response in a String.
JSONObject jsonObject = new JSONObject(response); // parse response into json object
JSONObject routeObject = jsonObject.getJSONObject("route"); // pull out the "route" object
JSONObject durationObject = jsonObject.getJSONObject("duration"); // pull out the "duration" object
String duration = durationObject.getString("text"); //this should be the duration text value (20 hours 40 mins)
You will have to wrap all that in a try-catch block to catch the JSONExceptions.
相关推荐
猜您喜欢
精彩图集
