我有一个问题要保存成位图文件。 我的方法是这样的：

I have a problem to save Bitmaps into files. My method is like this:

private File savebitmap(Bitmap bmp) {
    String extStorageDirectory = Environment.getExternalStorageDirectory()
            .toString();
    OutputStream outStream = null;

    File file = new File(bmp + ".png");
    if (file.exists()) {
        file.delete();
        file = new File(extStorageDirectory, bmp + ".png");
        Log.e("file exist", "" + file + ",Bitmap= " + bmp);
    }
    try {
        outStream = new FileOutputStream(file);
        bmp.compress(Bitmap.CompressFormat.PNG, 100, outStream);
        outStream.flush();
        outStream.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
    Log.e("file", "" + file);
    return file;

}

它给了我file.I的错误正在调用该方法是这样的：

It gives me error of file.I am calling this method like this:

Drawable d = iv.getDrawable();
Bitmap bitmap = ((BitmapDrawable) d).getBitmap();
File file = savebitmap(bitmap);

请帮我...

推荐答案

我尝试修改一下你的code 我假设你想使用的文件名，而不是位图作为参数

I try to make some corrections on your code I assume that you want to use filename instead of bitmap as parameter

 private File savebitmap(String filename) {
      String extStorageDirectory = Environment.getExternalStorageDirectory().toString();
      OutputStream outStream = null;

      File file = new File(filename + ".png");
      if (file.exists()) {
         file.delete();
         file = new File(extStorageDirectory, filename + ".png");
         Log.e("file exist", "" + file + ",Bitmap= " + filename);
      }
      try {
         // make a new bitmap from your file
         Bitmap bitmap = BitmapFactory.decodeFile(file.getName());

         outStream = new FileOutputStream(file);
         bitmap.compress(Bitmap.CompressFormat.PNG, 100, outStream);
         outStream.flush();
         outStream.close();
      } catch (Exception e) {
         e.printStackTrace();
      }
      Log.e("file", "" + file);
      return file;

   }