Dim xml = <Root>
            <Parent id="1">
              <Child>Thomas</Child>
            </Parent>
            <Parent id="2">
              <Child>Tim</Child>
              <Child>Jamie</Child>
            </Parent>
          </Root>

Dim parents = xml.Elements

在这种情况下，孩子包括所有的父元素，所有的子元素。什么是抢的只有直接的后裔最好的办法＆LT;根和GT; ？

In this case, children includes all the Parent elements and all of the Child elements. What's the best way to grab only the direct descendants of <Root>?

我应该写一个LINQ查询选择元素，其中母公司= ＆LT;根和GT; ？或者是有一些内置的方法，我很想念，可以让这对我？

Should I write a LINQ query that selects elements where parent = <Root>? Or is there some built-in method I'm missing that can get this for me?

编辑：我的一些混乱 XElement.Elements 和 XElement.Descendants 。由于鲁本Bartelink指出， XElement.Elements 会给我正是我所期待的。

I had some confusion between XElement.Elements and XElement.Descendants. As Ruben Bartelink pointed out, XElement.Elements will give me exactly what I was looking for.

谢谢！

推荐答案

Exec的总结 - 你想要的：

Exec summary - you want:

xml.Elements.Select(function(element) new XElement(element.Name,element.Attributes))

第一个答案：

First answer:

XElement.Descendants ，或者是一个有趣的问题？ ：P There's后人在这里的使用

XElement.Descendants, or is it a trick question ? :P There's an example of usage of Descendants here

修订的答案，谢谢托玛 - 什么事情也觉得不对劲：

Revised answer, thanks Tormod -- something did feel wrong!:

元素可以直接后裔，因为你要寻找的。后人提供了完整的层次[因为你是指控的元素呢。 （这个例子我联系到了这一点，道歉的混乱！

Elements gives direct descendants, as you're looking for. Descendants gives the full hierarchy [as you are alleging Elements does]. (The example I linked to makes this clear. Apologies for the confusion!

所以，最后，你要找的是什么（这个时候在VB中）：

So, finally, what you're looking for is (this time in VB):

Dim xml = <Root>
        <Parent id="1">
          <Child>Thomas</Child>
        </Parent>
        <Parent id="2">
          <Child>Tim</Child>
          <Child>Jamie</Child>
        </Parent>
      </Root>

REM All nodes two levels down in the hierarchy
Dim level2Nodes = xml.Elements.SelectMany(function(element) element.Elements)
level2Nodes.Dump

REM All Child nodes, no matter where they are:
Dim children = xml.Descendants("Child")

每个将产生你的3```元素，如包括在REMS不同的原因。

Each of which will yield you the 3 ``` elements for different reasons as covered in the REMs.

（粘贴上面直接进入 LINQPad 在VB中的语句模式）

(Paste the above directly into LINQPad in VB statement mode)

我现在看到的可能混淆你 - 当你使用的元素和看看它的Visualiser的，你仍然看到孩子们： -

I now see what might be confusing you - when you use Elements and look at it in a visualiser, you are still seeing the children:-

Dim parents = xml.Elements

如果您只想实际的名称，可以使用类似：

If you only want the actual names, you can use something like:

Dim parentNames = xml.Elements.Select(function(element) element.Name)

请注意，在每一种情况下，你得到两个结果

Note that in each of these cases, you are getting two results.

如果你真的想带出chidren，你想要的：

If you really want to strip out the chidren, you want:

Dim parentElements = xml.Elements.Select(function(element) new XElement(element.Name,element.Attributes))

您可以延长你的问题，以显示你真的想要？

Can you extend your question to show what you're really looking for?