最后的ViewGroup layout6 =（ViewGroup中）LayoutInflater.from（
                           Menus.this）.inflate（
                           R.layout.beefkabobsandwhichdialog，NULL）;

AlertDialog.Builder Builder6的=新AlertDialog.Builder（Menus.this）;

builder6.setView（layout6）;

builder6.setView（LayoutInflater.from（Menus.this）.inflate（
        R.layout.beefkabobsandwhichdialog，NULL））;

builder6.setPositiveButton（Add2Order
        新DialogInterface.OnClickListener（）{
            公共无效的onClick（DialogInterface对话，诠释它）{
                验证（（（的EditText）layout6
                .findViewById（R.id.quantityedittext1））
                。.getText（）的toString（））;
            }
        }）;
 

解决方案

您对话的内容不设置layout6。你有第二个 builder6.setView（）在那里。这就是为什么Android无法找到的EditText 的ID。另外，也许你可以有更多的描述性的变量名。 ：）

final ViewGroup layout6 = (ViewGroup) LayoutInflater.from(
                           Menus.this).inflate(
                           R.layout.beefkabobsandwhichdialog, null);

AlertDialog.Builder builder6 = new AlertDialog.Builder(Menus.this);

builder6.setView(layout6);

builder6.setView(LayoutInflater.from(Menus.this).inflate(
        R.layout.beefkabobsandwhichdialog, null));

builder6.setPositiveButton("Add2Order",
        new DialogInterface.OnClickListener() { 
            public void onClick(DialogInterface dialog,int which) {
                validate(((EditText) layout6
                .findViewById(R.id.quantityedittext1))
                .getText().toString());
            }
        });

Your dialog's content is not set with layout6. You have a second builder6.setView() in there. That is why Android cannot find the EditText's ID. Also, maybe you can have more descriptive variable names. :)