我工作的Andr​​oid应用程序。在我的应用程序我有字符串转换为JSON对象，然后解析值。我检查了计算器中的一个解决方案，并发现了类似的问题在这里link

解决的办法是这样的

 `{phonetype：N95，猫：WP}`
        JSONObject的jsonObj =新的JSONObject（{\phonetype \：\N95 \，\猫\：\WP \}）;
 

我用同样的方法在我的code。我的字符串是

{"ApiInfo":{"description":"userDetails","status":"success"},"userDetails":{"Name":"somename","userName":"value"},"pendingPushDetails":[]} 串了mystring = mystring.replace（\，\\\）;

和更换后，我得到的结果，因为这

{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"Sarath巴布\，\用户名\：\sarath.babu.sarath巴布\，\令牌\：\ZIhvXsZlKC​​NL6Xj9OPIOOz3FlGta9g \，\用户id \：\118 \} \pendingPushDetails \ ：[]}

当我执行的JSONObject jsonObj =新的JSONObject（mybizData）;

我收到下面的JSON异常

  org.json.JSONException：在性格1期望的文字值
 

请帮我解决我的问题。

解决方案

删除斜杠：

  JSON字符串= {phonetype：N95，猫：WP};

尝试 {

    JSONObject的OBJ =新的JSONObject（JSON）;

    Log.d（我的应用，obj.toString（））;

}赶上（的Throwable T）{
    Log.e（我的应用，无法解析畸形的JSON：\+ JSON +\）;
}
 

I am working on an Android application. In my app I have to convert a string to Json Object, then parse the values. I checked for a solution in stackoverflow and found similar issue here link

The solution is like this

       `{"phonetype":"N95","cat":"WP"}`
        JSONObject jsonObj = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");

I use the same way in my code . My string is

{"ApiInfo":{"description":"userDetails","status":"success"},"userDetails":{"Name":"somename","userName":"value"},"pendingPushDetails":[]}

string mystring= mystring.replace("\"", "\\\"");

And after replace I got the result as this

{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"Sarath Babu\",\"userName\":\"sarath.babu.sarath babu\",\"Token\":\"ZIhvXsZlKCNL6Xj9OPIOOz3FlGta9g\",\"userId\":\"118\"},\"pendingPushDetails\":[]}

when I execute JSONObject jsonObj = new JSONObject(mybizData);

I am getting the below json exception

org.json.JSONException: Expected literal value at character 1 of

Please help me to solve my issue.

解决方案

Remove the slashes:

String json = {"phonetype":"N95","cat":"WP"};

try {

    JSONObject obj = new JSONObject(json);

    Log.d("My App", obj.toString());

} catch (Throwable t) {
    Log.e("My App", "Could not parse malformed JSON: \"" + json + "\"");
}