如何从WebViewClient打开新的浏览器?开新、浏览器、WebViewClient

2023-09-04 05:52:00 作者:Poikilotherm

短的问题,我不能让我的手指上,我想推出一个新的浏览器从我的WebView人后单击超链接。但是,我怎么可以设置该链接逃离WebViewClient的这个目标?

下面是我的code,任何帮助是极大的AP preciated:

 的WebView网站=(web视图)findViewById(R.id.WebView);
  site.setWebViewClient(新WebViewClient());
  site.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
  site.getSettings()setJavaScriptEnabled(真)。

  button1.setOnClickListener(button1OnClickListener);
  button2.setOnClickListener(button2OnClickListener);
  button3.setOnClickListener(button3OnClickListener);
  button4.setOnClickListener(button4OnClickListener);


  最后AlertDialog alertDialog =新AlertDialog.Builder(本).create();

  进度= ProgressDialog.show(FlitsersActivity.this,Thingy1,载入...,假的,真正的);

  site.setWebViewClient(新WebViewClient(){
   公共布尔shouldOverrideUrlLoading(web视图查看,字符串URL){
       Log.i(TAG,正在加载...);
       view.loadUrl(URL);
       返回true;
   }

   公共无效onPageFinished(web视图查看,字符串URL){
       Log.i(TAG,完成:+网址);
       如果(progressBar.isShowing()){
           progressBar.dismiss();
       }
   }

   公共无效onReceivedError(web视图来看,INT错误code,字符串描述,字符串failingUrl){
       Log.e(TAG,错误:+说明);
       Toast.makeText(MyActivity.this,哦,不!+描述,Toast.LENGTH_SHORT).show();
       alertDialog.setTitle(错误);
       alertDialog.setMessage(介绍);
       alertDialog.setButton(OK,新DialogInterface.OnClickListener(){
           公共无效的onClick(DialogInterface对话,诠释它){
               返回;
           }
       });
       alertDialog.show();
   }
 });

 site.loadUrl(http://www.etcetera.com);

}
 

解决方案

没错,谢谢!我想我找到了你周围写的第二个响应的时间;)

现在,我使用code以下:它就像一个魅力:)非常感谢你的回应

  site.setWebViewClient(新WebViewClient(){
   公共布尔shouldOverrideUrlLoading(web视图查看,字符串URL){
       字符串myAlternativeURL =HTTP://的newURL;
       如果(!url.equals(myAlternativeURL)){
           {
               意图I =新的意图(Intent.ACTION_VIEW);
               i.setData(Uri.parse(的http://的newURL));
               startActivity(ⅰ);
               }
           返回true;
       } 其他 {
       Log.i(TAG,正在加载...);
       view.loadUrl(URL);
       返回true;
   }
   }
 
火狐浏览器里的restClient插件怎么用

Short question that i cannot get my finger on, i'd like to launch a new browser from my WebView after people click a hyperlink. But how can i set that target of that link to escape the WebViewClient??

Here's my code, any help is greatly appreciated:

WebView site = (WebView)findViewById(R.id.WebView);
  site.setWebViewClient(new WebViewClient());
  site.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
  site.getSettings().setJavaScriptEnabled(true);

  button1.setOnClickListener(button1OnClickListener);
  button2.setOnClickListener(button2OnClickListener);
  button3.setOnClickListener(button3OnClickListener);
  button4.setOnClickListener(button4OnClickListener);


  final AlertDialog alertDialog = new AlertDialog.Builder(this).create();

  progressBar = ProgressDialog.show(FlitsersActivity.this, "Thingy1", "Load...", false, true);

  site.setWebViewClient(new WebViewClient() {
   public boolean shouldOverrideUrlLoading(WebView view, String url) {
       Log.i(TAG, "Loading...");
       view.loadUrl(url);
       return true;
   }

   public void onPageFinished(WebView view, String url) {
       Log.i(TAG, "Done: " +url);
       if (progressBar.isShowing()) {
           progressBar.dismiss();
       }
   }

   public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
       Log.e(TAG, "Error: " + description);
       Toast.makeText(MyActivity.this, "Oh no! " + description, Toast.LENGTH_SHORT).show();
       alertDialog.setTitle("Error");
       alertDialog.setMessage(description);
       alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
           public void onClick(DialogInterface dialog, int which) {
               return;
           }
       });
       alertDialog.show();
   }
 });

 site.loadUrl("http://www.etcetera.com");

}

解决方案

Exactly, thanks! I think i found out around the time you wrote the second response ;)

Right now i am using the code below: it works like a charm :) Thank you very much for responding!

site.setWebViewClient(new WebViewClient() {
   public boolean shouldOverrideUrlLoading(WebView view, String url) {
       String myAlternativeURL = "http://newURL";  
       if (!url.equals(myAlternativeURL)) {  
           {
               Intent i = new Intent(Intent.ACTION_VIEW);
               i.setData(Uri.parse("http://newURL"));
               startActivity(i);
               }
           return true;  
       } else {
       Log.i(TAG, "Loading...");
       view.loadUrl(url);
       return true;
   }
   }