我从@DanS下面code这个链接how-to-display-a-map-still-image-file-with-a-moving-current-location

I got the below code from @DanS at this link how-to-display-a-map-still-image-file-with-a-moving-current-location

onCurrentPosition(Location current){
    double hypotenuse = upperLeft.distanceTo(current);
    double bearing = upperLeft.bearingTo(current);
    double currentDistanceX = Math.cos(bearing) * hypotenuse;
    //                     "percentage to mark the position"
    double currentPixelX = (currentDistanceX / upperLeft.distanceTo(lowerRight) * Math.cos(upperLeft.bearingTo(lowerRight))) * mapWidth;

    moveIndicatorX(currentPixelX);
}

下面是值：

电流：41.850033，-87.65005229999997 upperLeft：41.866514127810355，-87.6720142364502 lowerRight：41.83397145565242，-87.62824058532715 mapWidth：512×512像素

下面是计算器在线位置，斜边（距离），轴承（方位角）

Here are the calculator online for Location, hypotenuse(Distance), bearing(Azimuths)

转换经纬度来定位的格式（例如41°51'59.45N 87°40'19.25 W） 计算距离和放大器;从给定的位置方位 convert LatLng to Location format(e.g. 41° 51′ 59.45″ N 87° 40′ 19.25″ W) compute distance & azimuths from the given Location

我得到的结果：

斜边= 2581 轴承= 135.21 currentDistanceX = -2562 currentPixelX = 311.9

想问问你们到：

以确认如果我的计算结果是正确的。 如何计算currentPixelY（在1分）？ to confirm if my computed results are correct. on how to compute the currentPixelY (the another one point)?

顺便说一句，我打算用它来计算给定的现实生活中的位置的经纬度（电流）对我的静止图像地图，保税静止图像转化为现实生活中经纬度的upperLeft和lowerRight角落。

By the way, I am planning to use that to compute the location of a given real life LatLng(current) against with my still image map which bonded the upperLeft and lowerRight corners of the still image into real life LatLng.

如果你想看到的实际和放大器;预期产出，想方便地了解全貌。请参考此链接 - > How标记当前位置为静止图像地图

If you want to see the actual & expected output and want to easily understand the whole picture. Please refer to this link -> How to mark the current location into a still image map

推荐答案

这是实际的code我用，而不是伪code贴previously：

This is the actual code I'm using, not pseudo code posted previously:

Location upperLeft = new Location("");
upperLeft.setLatitude(41.866514127810355);
upperLeft.setLongitude(-87.6720142364502);
Location lowerRight = new Location("");
lowerRight.setLatitude(41.83397145565242);
lowerRight.setLongitude(-87.62824058532715);
Location current = new Location("");
current.setLatitude(41.850033);
current.setLongitude(-87.65005229999997);
double hypotenuse = upperLeft.distanceTo(current);
double bearing = upperLeft.bearingTo(current);
double currentDistanceX = Math.cos(bearing * Math.PI / 180.0) * hypotenuse;
//                     "percentage to mark the position"
double totalHypotenuse = upperLeft.distanceTo(lowerRight);
double totalDistanceX = totalHypotenuse * Math.cos(upperLeft.bearingTo(lowerRight) * Math.PI / 180.0);
double currentPixelX = currentDistanceX / totalDistanceX * 512;

System.out.println(currentPixelX); // 259.3345493341548

您计算出答案看起来有点假。 为了计算y变为复制所有的X标记的计算和变量使用 Math.sin（）而不是 Math.cos（）。

Your calculated answer looks a bit off. To calculate Y change copy all the X marked calculations and variables to use Math.sin() instead of Math.cos().