的.java没有使用2或3个参数的查看构造; XML属性将无法正常工作无法正常、属性、参数、工作

2023-09-04 05:24:10 作者:举起你的手

我是新手我有问题,创建游戏

i'm newbie i have problem creating game

执行程序

activity_main.xml - > MainActivity.java - > GameLoop.java - > action.xml(错误) - > CustomView.java

activity_main.xml -> MainActivity.java -> GameLoop.java -> action.xml (error) -> CustomView.java

Custom view CustomView is not using the 2- or 3-argument View constructors; XML attributes will not work

我不明白......

I don't understand......

推荐答案

您需要覆盖其他2构造鉴于CustomView:

You need to override the other 2 constructors of View in CustomView:

public CustomView(Context context) {
    super(context);
    init(context);
}

public CustomView(Context context, AttributeSet attrs) {
    super(context, attrs);
    init(context);
}

public CustomView(Context context, AttributeSet attrs, int defStyle) {
    super(context, attrs, defStyle);
    init(context);
}

private void init(Context context) {
    //do stuff that was in your original constructor...
}