我目前正在开发一个数学的应用，使长计算。每当我键入一个整数，其中超过9位数...的错误（其中...被替换为一个很长的数字）：我收到java.lang.NumberFormatException：无效INT。当我输入一个整数，它是小于或等于9位，应用程序运行正常。我需要的输出为一个int（即没有小数位）。不明白为什么错误的发生。

的code这是造成问题的位是：

 意向意图= getIntent（）;
字符串消息= intent.getStringExtra（MainActivity.NUMBER）;
INT INP =的Integer.parseInt（消息）;
 

解决方案

对于最大值 INT 2 31 -1，即2,147,483,647。如果你试图解析比数字越大，会抛出异常。

如果您需要处理更大的数字，可以使用长对于一般较大范围（高达2 63 -1）或的BigInteger 为任意大小。

I'm currently developing a math application that makes long computations. I'm getting java.lang.NumberFormatException: Invalid int: "..." error (where the ... is replaced by a very long number) whenever I type an integer that contains more than 9 digits. When I type in an integer that is less than or equal to 9 digits, the application runs fine. I need the output to be an int (i.e. no decimal places). Not quite sure why the error's occurring.

The bit of code that's causing the problem is:

Intent intent = getIntent();
String message = intent.getStringExtra(MainActivity.NUMBER);
int inp = Integer.parseInt(message);

The maximum value for an int is 231-1, i.e. 2,147,483,647. If you try to parse a larger number than that, the exception will be thrown.

If you need to handle larger numbers, either use long for a generally larger range (up to 263-1) or BigInteger for an arbitrary size.