假设我们有100个字符串，你从R.string.xml让他们的阵列。

Suppose we have an array of 100 Strings, which you get them from R.string.xml.

private String lapi[]={"R.string.lapi0", "R.string.lapi1", "R.string.lapi2", "R.string.lapi3"..."R.string.lapi99};

另外，我们有一个TextView和一个Button：

Also we have a TextView and a Button:

pelicula=(TextView)findViewById(R.id.lapicera);
btnElegir=(Button)findViewById(R.id.btnElegir);

和我们想，当我们点击按钮让我们0到100之间的随机值：

and we want that when we click the button get us a random value between 0 and 100:

int random=(int) Math.round(Math.random()*100);

问题：什么是编辑的TextView使用到的随机值所属的数组值的最简单的方法？ 我想要做的是这样的：

The problem: what would be the easiest way to edit the TextView with the array value to which the random value belongs ?. What I want to do is something like this:

pelicula.setText(getResources().getString(lapi[random]));

这是我认为最有效的解决方案，但不起作用。

That is the most effective solution I thought, but doesn't work.

你知道，如果有其他类似的工作，这样一来？，而不必使用一个开关。

Do you know if there are other similar work as this way ?, without having to use a switch.

很抱歉，如果我的英语不太清楚。

Sorry if my english isn't clear.

在此先感谢！

推荐答案

的getString（）预计资源ID，你只是给一个String（即使它对应同一个文本的ID，它只是一个字符串）。

getString() expects the resource id, you are just giving a String (even if it "corresponds" to the same textual id, it's just a String).

您想实现是可以做到用 则getIdentifier（） （你甚至不需要数组）：

What you want to achieve can be done using getIdentifier() (and you don't even need the array):

Random r = new Random();
...
int randomId = r.nextInt(100);
int resID = getResources().getIdentifier("lapi"+randomId, "string", getPackageName());
pelicula.setText(resID);

请注意，这是更有效的检索与ID的资源，为DOC状态：

Be aware that it's more efficient to retrieve the resource with the id, as the doc states:

注：该函数的使用是不鼓励。它是更有效   检索由标识符资源比的名字。

Note: use of this function is discouraged. It is much more efficient to retrieve resources by identifier than by name.