我想解析使用SAX解析器我的应用程序的XML响应，我不知道该怎么做，所以任何人都可以请giude我在正确的道路。

用少许编码或一个链接的一个例子将是确定。 谢谢， 大卫

 尝试{
        HttpClient的客户端=新DefaultHttpClient（）;
        串的getURL =＆其中; URL取代;
        HTTPGET GET =新HTTPGET（的getURL）;
        HTT presponse responseGet = client.execute（获得）;
         mResEntityGet = responseGet.getEntity（）;
        如果（mResEntityGet！= NULL）{
            //做一些与响应
            内容= EntityUtils.toString（mResEntityGet）;
        }
    }赶上（例外五）{
        e.printStackTrace（）;
    }
 

内容将是XML格式的字符串，使用XML拉式解析器解析它。

I want to Parse the XML Response in my Application using a SAX PArser, I don't know how to do that, So Can anybody please giude me to the right path.

An example with a little coding or a link will be OK. Thanks, david

try {
        HttpClient client = new DefaultHttpClient();
        String getURL = <URL>;
        HttpGet get = new HttpGet(getURL);
        HttpResponse responseGet = client.execute(get);
         mResEntityGet = responseGet.getEntity();
        if (mResEntityGet != null) {
            //do something with the response
            content = EntityUtils.toString(mResEntityGet);
        }
    } catch (Exception e) {
        e.printStackTrace();
    }

"content" will be the string of XML format, parse it using XML pull parser.