我在2008年SQLSERVER数据库作为二进制存储IPv4地址(4)。所以,我的数据输入转换前的值(并且由于公司限制,我无法创建功能的数据库里面,还有那不是再讨论)。
I'm storing an IPV4 address on a SQLSERVER 2008 database as Binary(4). So, I'm converting the values before data input (and due to company restrictions I CANNOT create functions inside the db, well thats not up for discussion).
public static byte[] IpToBin(string ip)
{
return IPAddress.Parse(ip).GetAddressBytes();
}
public static string HexToIp(string ip)
{
return new IPAddress(long.Parse(ip, NumberStyles.HexNumber)).ToString();
}
IpToBin称为后,所产生的数据是(例如0x59FC09F3)。当我打电话HexToIp的IP颠倒过来可能是由于小/大端转换。
After IpToBin is called, the data generated is (for example 0x59FC09F3). When I call HexToIp the ip came reversed probably due little/big endian conversion.
任何人都可以,请拿出一个像样的解决方案,不带50十亿行code?
Could anyone please come up with a decent solution without 50 billion lines of code?
我觉得这里真正的问题是,你正在处理的原始形式的字符串;特别是因为它是二进制(4)
,你不应该这样做:只是把它抓回来从DB作为字节[]
。 IpToBin
是好的,但 HexToIp
也许应该是:
I think the real issue here is that you are treating the raw form as a string; especially since it is binary(4)
, you should never have to do that: just fetch it back from the db as a byte[]
. IpToBin
is fine, but HexToIp
should probably be:
public static IPAddress BinToIp(byte[] bin)
{
return new IPAddress(bin);
}
那么:完成任务。但是,与现有的 HexToIp
code,你想要的:
then: job done. But with your existing HexToIp
code, you want:
return new IPAddress(new byte[] {
Convert.ToByte(ip.Substring(0,2), 16), Convert.ToByte(ip.Substring(2,2), 16),
Convert.ToByte(ip.Substring(4,2), 16), Convert.ToByte(ip.Substring(6,2), 16)}
).ToString();