我有一个 System.Drawing.Bitmap
,并在4个点(的形成矩形 Vector2 ■哪些被轻易地转化成
的PointF
S)。
I have an image in the form of a System.Drawing.Bitmap
and a rectangle in the form of 4 points (Vector2
s which are trivially converted to PointF
s).
我想用这些点裁剪出的图像的部分。我发现这个答案是pretty的接近我想要的,但我不知道怎么弄的正确的矩阵出来。
I want to use those points to crop out a section of the image. I found this answer which is pretty close to what I want, but I'm not sure how to get the right matrix out of it.
下面是我有这么远:
protected static Bitmap CropImage(Bitmap src, Vector2[] rect)
{
var width = (rect[1] - rect[0]).Length;
var height = (rect[3] - rect[0]).Length;
var result = new Bitmap(M2.Round(width), M2.Round(height));
using (Graphics g = Graphics.FromImage(result))
{
g.InterpolationMode = InterpolationMode.HighQualityBicubic;
using (Matrix mat = new Matrix())
{
// ????
}
}
return result;
}
我怎样才能得到适当的变换矩阵我的矩形的?
How can I get the proper transform matrix out of my rect?
想通了:
protected static Bitmap CropImage(Bitmap src, Vector2[] rect)
{
var width = (rect[1] - rect[0]).Length;
var height = (rect[3] - rect[0]).Length;
var result = new Bitmap(M2.Round(width), M2.Round(height));
using (Graphics g = Graphics.FromImage(result))
{
g.InterpolationMode = InterpolationMode.HighQualityBicubic;
using (Matrix mat = new Matrix())
{
var rot = -Math.Atan2(rect[1].Y - rect[0].Y, rect[1].X - rect[0].X) * M2.RadToDeg;
mat.Translate(-rect[0].X, -rect[0].Y);
mat.RotateAt((float)rot, rect[0].ToPointF());
g.Transform = mat;
g.DrawImage(src, new Rectangle(0, 0, src.Width, src.Height));
}
}
return result;
}