我如何加载以下格式的XML文档：

How can I load the following formatted XML document:

<Settings>
    <MimeTypes>
        <MimeType Type="application/mac-binhex40" Extensions=".hqx"/>
        <MimeType Type="application/msword" Extensions=".doc;.docx"/>
        <MimeType Type="application/pdf" Extensions=".pdf"/>
        <MimeType Type="application/vnd.ms-excel" Extensions=".xla;.xlc;.xlm;.xls;.xlt;.xlw;.xlsx"/>
    </MimeTypes> 
</Settings>

成一本字典，其中的关键是个人的扩展，其值是MIMETYPE。

Into a dictionary where the key is an individual extension, and the value is the mimetype.

因此​​，对于这一行：

So, for this line:

<MimeType Type="application/vnd.ms-excel" Extensions=".xla;.xlc;.xlm;.xls;.xlt;.xlw;.xlsx"/>

我想有以下键值项：

I would have the following key-value entries:

键：.xla价值：应用程序/ vnd.ms-Excel的 键：.xlc价值：应用程序/ vnd.ms-Excel的 键：.xlm工作的价值：应用程序/ vnd.ms-Excel的 键：.xls的价值：应用程序/ vnd.ms-Excel的 键：名为.xlt的价值：应用程序/ vnd.ms-Excel的

Key: ".xla" Value: "application/vnd.ms-excel" Key: ".xlc" Value: "application/vnd.ms-excel" Key: ".xlm" Value: "application/vnd.ms-excel" Key: ".xls" Value: "application/vnd.ms-excel" Key: ".xlt" Value: "application/vnd.ms-excel"

我是比较新的LINQ到XML的业务。

I'm relatively new to the LINQ-To-XML business.

我知道我应该在文件中加载到像的XElement：

I know that I should load in the document into an XElement like:

 XElement settingsDoc = XElement.Load("Settings.xml");

然而，怎么做我选择所有Mime类型项？

However, how to do I select all "MimeType" entries?

推荐答案

是这样的：

 var dictionary = (from element in settingsDoc.Descendants("MimeType")
                   from extension in element.Attribute("Extensions")
                                         .Value.Split(';')
                   select new { Type = element.Attribute("Type").Value,
                                Extension = extension })
                   .ToDictionary(x => x.Extension,
                                 x => x.Type);