如何重定向到FastAPI终结点内动态URL重定向、动态、FastAPI、URL

2023-09-04 01:58:01 作者:女中豪杰

我正在做一个功能,用户在他们的个人资料页面上进行更改(与用户模型无关)。一切都是通过静态html模板实现的。我需要用户点击按钮,并返回到同一页(他们的个人资料页)后处理的请求。 html

<td><a href="{{ url_for('decline_event_invite', pk=invite.id) }}" class="btn blue lighten-2">Accept</a></td>

endpoint ts.py

@router.get('/invite/{pk}/decline')
async def decline_event_invite(
        request: Request,
        pk: int,
        user_id: str = Depends(get_current_user),
        service: InviteService = Depends(),
):
    await service.invite_decline(pk)
    ...
    --> here I want redirect to user profile page 
    return RedirectResponse('DYNAMIC URL WITH ARGS')
DreamFacotry 第4章 如何保护REST API

profile.py

@router.get('/{pk}')
async def user_profile(
        request: Request,
        pk: int,
        service: UserService = Depends()
):
    user = await service.get_user_info(pk)
    events_invites = await service.get_user_events_invite_list(pk)
    return templates.TemplateResponse(
        'profile.html',
        context=
        {
            'request': request,
            'user': user,
            'events_invites': events_invites,
        }
    )

但我在任何地方都找不到如何执行类似于应用于模板的逻辑的重定向。例如

<a href="{{ url_for('user_profile', pk=pk) }}">Sender</a>

推荐答案

可以使用url_for()函数并传递(**kwargs)路径参数。

import uvicorn
from fastapi import FastAPI, Request
from fastapi.templating import Jinja2Templates
from fastapi.responses import RedirectResponse
import urllib
from fastapi import APIRouter

router = APIRouter()

templates = Jinja2Templates(directory="templates")

@router.get('/invite/{pk}/decline')
async def decline_event_invite(request: Request, pk: int):
    redirect_url = request.url_for('user_profile', **{ 'pk' : pk})
    return RedirectResponse(redirect_url)    

@router.get('/{pk}')
async def user_profile(request: Request, pk: int):
    return templates.TemplateResponse("profile.html", {"request": request, "pk": pk})
    
if __name__ == "__main__":
    uvicorn.run(router, host='127.0.0.1', port=8000, debug=True)

如果您还需要传递查询参数,请使用以下示例代码(确保导入urllib):

parsed = list(urllib.parse.urlparse(redirect_url))
parsed[4] = urllib.parse.urlencode({**{ 'username' : "name"}})
new_redirect_url = urllib.parse.urlunparse(parsed)