目前我有一个字节[]
包含图像文件的所有数据,只是想建立 HttpPostedFileBase ,这样我就可以使用,而不是创建一个新的重载之一的现有方法。
公众的ActionResult保存(HttpPostedFileBase文件)
公众的ActionResult保存(byte []的数据)
{
//希望我可以在这里再构造HttpPostedFileBase的一个实例
返回保存(文件);
//而不是写了很多类似codeS的
}
解决方案
创建一个派生类,如下所示:
类MemoryFile:HttpPostedFileBase
{
流流;
字符串的contentType;
字符串文件名;
公共MemoryFile(流流,字符串的contentType,字符串文件名)
{
this.stream =流;
this.contentType的contentType =;
this.fileName =文件名;
}
公众覆盖INT CONTENTLENGTH
{
{返回(INT)stream.Length; }
}
公共重写字符串的ContentType
{
{返回的contentType; }
}
公众覆盖字符串文件名
{
{返回文件名; }
}
公共覆盖流的InputStream
{
{返回流; }
}
公众覆盖无效另存为(字符串文件名)
{
使用(var文件= File.open方法(文件名,FileMode.CreateNew))
stream.CopyTo(文件);
}
}
现在,你可以通过这个培训班里HttpPostedFileBase预期的实例。
Currently I have a byte[]
that contains all the data of an image file, just want to build an instance of HttpPostedFileBase
so that I can use an existing method, instead of creating a new overload one.
public ActionResult Save(HttpPostedFileBase file)
public ActionResult Save(byte[] data)
{
//Hope I can construct an instance of HttpPostedFileBase here and then
return Save(file);
//instead of writing a lot of similar codes
}
解决方案
Create a derived class as follows:
class MemoryFile : HttpPostedFileBase
{
Stream stream;
string contentType;
string fileName;
public MemoryFile(Stream stream, string contentType, string fileName)
{
this.stream = stream;
this.contentType = contentType;
this.fileName = fileName;
}
public override int ContentLength
{
get { return (int)stream.Length; }
}
public override string ContentType
{
get { return contentType; }
}
public override string FileName
{
get { return fileName; }
}
public override Stream InputStream
{
get { return stream; }
}
public override void SaveAs(string filename)
{
using (var file = File.Open(filename, FileMode.CreateNew))
stream.CopyTo(file);
}
}
Now you can pass instance of this class where HttpPostedFileBase is expected.