未知数量清单的C相交#.NET清单、数量、NET

2023-09-03 06:07:26 作者:拥你心安i

我有一个字典< INT,列表和LT;字符串>> ,我想相交所有列表的每个INT

I have a dictionary<int, List<string>> and I want to intersect all of the lists for each int.

我将如何做到这一点?我觉得这应该是容易的,但由于某种原因它不工作了。

How would I achieve that? I feel like this should be easy, but for some reason it's not working out.

感谢。

推荐答案

这是很容易来循环列表的顺序,把第一次到的HashSet ,然后相互交叉子列表吧:

It's easy enough to iterate the sequence of lists, putting the first into a HashSet and then intersecting each subsequence list with it:

public static IEnumerable<T> intersectAll<T>(IEnumerable<IEnumerable<T>> source)
{
    using (var iterator = source.GetEnumerator())
    {
        if (!iterator.MoveNext())
            return Enumerable.Empty<T>();

        var set = new HashSet<T>(iterator.Current);
        while (iterator.MoveNext())
            set.IntersectWith(iterator.Current);

        return set;
    }
}

使用这个你可以写 IntersectAll(dictionary.Values​​.Cast&LT; IEnumerable的&LT;字符串&GT;&GT;())。获取路口