我愿做这样的事情的下文。什么函数返回我打开了一个独特的文件？这样我就可以确保它是我的，我不会覆盖任何内容或编写复杂的FN生成/循环

 的BinaryWriter W = GetTempFile（出FN）;
w.close（）;
File.Move（FN，newFn）;
 

解决方案

有两种方法如下：

Path.GetTempFileName

这将创建一个临时文件，并返回其名称。

Path.GetRandomFileName

这将使用保密性强的随机字符串作为文件名，并不会为你的文件。

通常第一种方法就足够了;对于GetRandomFileName该文件说：

当你的文件系统的安全性是最重要的，应该用来代替GetTempFileName这种方法。

I would like to do something like the below. What function returns me an unique file that is opened? so i can ensure it is mine and i wont overwrite anything or write a complex fn generate/loop

BinaryWriter w = GetTempFile(out fn);
w.close();
File.Move(fn, newFn);

There are two methods for this:

Path.GetTempFileName

This will create a temporary file and return its name.

Path.GetRandomFileName

This will use a cryptographically strong, random string as file name and won't create the file for you.

Usually the first method suffices; the documentation for GetRandomFileName says:

When the security of your file system is paramount, this method should be used instead of GetTempFileName.