在以下code 的messageReceived 是在不同的线程卷标1 ，并试图访问它时，我会得到这个错误：

跨线程操作无效：   控制LABEL1从访问   线程比线程这是其他   上创建。

  foo.MessageReceived + =新Agent.MessageReceivedHandler（foo_MessageReceived）;

无效foo_MessageReceived（消息消息）
{
   label1.Text = message.Body;
}
 

我该如何解决这个问题？

更多：显然我需要使用代理和引用，但我不知道如何，能否请您详细介绍一下？

请永远相信你的主线程（GUI线程）上更新您的图形用户界面。

foo.MessageReceived + =新Agent.MessageReceivedHandler（foo_MessageReceived）;

 公共委托无效MyDelegate（信息MSG）;
无效foo_MessageReceived（消息消息）
{
   如果（InvokeRequired）
   {
      的BeginInvoke（新MyDelegate（foo_MessageReceived），新的对象[] {消息}）;
   }
   其他
   {
      label1.Text = message.Body;
   }
}
 

In the following code MessageReceived is on a different thread to label1 and when trying to access it I will get this error:

Cross-thread operation not valid: Control 'label1' accessed from a thread other than the thread it was created on.

foo.MessageReceived += new Agent.MessageReceivedHandler(foo_MessageReceived); 

void foo_MessageReceived(Message message)
{
   label1.Text = message.Body;
}

How can I solve this?

More: apparently I need to use delegate and invoke, but I don't know how, can you please explain in more detail?

Make always sure you update your GUI on the main thread (GUI thread).

foo.MessageReceived += new Agent.MessageReceivedHandler(foo_MessageReceived);

public delegate void MyDelegate(Message msg);
void foo_MessageReceived(Message message)
{ 
   if (InvokeRequired)
   {
      BeginInvoke(new MyDelegate(foo_MessageReceived),new object[]{message});
   }
   else
   {
      label1.Text = message.Body;
   }
}