我不知道我问的东西是否有效，但我只是想知道，如果它的存在以及它是如何工作的。因此，这里是我的问题：

I don't know the thing I am asking is available or not but I just want to know if it exists and how it works. So here is my question:

我有我自己的2-3自定义模型类。例如，客户，   员工和产品。现在我有一个字符串类的名称。和基于   类的名字进来的字符串，我要创建的对象，   返回到视图。我怎么能做到这一点？

I have 2-3 custom model class of my own. For example, Customer, Employee and Product. Now I have class name in a string. and based on the class name coming in a string, I have to create its object and return to a VIEW. How could I achieve this?

我知道的if else 语句中的选择，但我想尝试一个更美好，动态的方式......

I know a option of IF ELSE statement but I want to try a better,"Dynamic" way...

推荐答案

有类名的字符串是不够的，能够创建它的实例。 作为事实上，你需要完整的命名空间包括类名来创建一个对象。

Having the class name in string is not enough to be able to create its instance. As a matter of fact you will need full namespace including class name to create an object.

假设你具备以下条件：

string className = "MyClass";
string namespaceName = "MyNamespace.MyInternalNamespace";

比你可以创建一个类的实例，类对象 MyNamespace.MyInternalNamespace.MyClass 通过以下任一方法：

Than you you can create an instance of that class, the object of class MyNamespace.MyInternalNamespace.MyClass using either of the following techniques:

var myObj = Activator.CreateInstance(namespaceName, className);

或者这样的：

or this:

var myObj = Activator.CreateInstance(Type.GetType(namespaceName + "." + className));

希望这会有所帮助，请让我知道如果没有。

Hope this helps, please let me know if not.