AutoMapper ConvertUsing()AutoMapper、ConvertUsing

2023-09-03 02:26:45 作者:琉璃

我的对象不具有默认的构造函数,它们都需要一个签名

My objects don't have a default constructor, they all require a signature of

new Entity(int recordid);

我添加以下行:

I added the following line:

Mapper.CreateMap<EntityDTO, Entity>().ConvertUsing(s => new Entity(s.RecordId));

这修复了Automapper期待一个默认的构造函数的问题,但是,它映射的唯一元素是记录的ID。

This fixes the problem where Automapper is expecting a default constructor, however the only element that is mapped is the record id.

我如何得到它拿起这是正常的映射?如何去映射实体的所有属性,而不必手动映射属性?

How do I get it to pick up on it's normal mapping? How to get all the properties of the entities to be mapped without having to manually map the properties?

推荐答案

您可以使用 ConstructUsing 而不是 ConvertUsing 。下面是一个演示:

You could use ConstructUsing instead of ConvertUsing. Here's a demo:

using System;
using AutoMapper;

public class Source
{
    public int RecordId { get; set; }
    public string Foo { get; set; }
    public string Bar { get; set; }
}

public class Target
{
    public Target(int recordid)
    {
        RecordId = recordid;
    }

    public int RecordId { get; set; }
    public string Foo { get; set; }
    public string Bar { get; set; }
}


class Program
{
    static void Main()
    {
        Mapper
            .CreateMap<Source, Target>()
            .ConstructUsing(source => new Target(source.RecordId));

        var src = new Source
        {
            RecordId = 5,
            Foo = "foo",
            Bar = "bar"
        };
        var dest = Mapper.Map<Source, Target>(src);
        Console.WriteLine(dest.RecordId);
        Console.WriteLine(dest.Foo);
        Console.WriteLine(dest.Bar);
    }
}