我需要分析一个十进制整数出现在一个字符串的开始。

可能有尾随垃圾以下的十进制数。这需要被忽略（即使它包含其它数目。）

例如。

 1=＆GT; 1
42=＆GT; 42
3 -.X.-=＆GT; 3
2 3 4 5=＆GT; 2
 

有一个内置的方式在.NET框架来做到这一点？

int.TryParse（）是不适合的。它允许尾随空格而不是其他尾随字符。

这将是很容易实现这一点，但我想preFER如果存在使用标准方法。

 的foreach（VAR在Regex.Matches M（3  -  .X 4，@\ D +） ）
{
    Console.WriteLine（米）;
}
 

每秒更新注释

不知道为什么你不喜欢经常EX pressions，所以我就寄我觉得是最短的解决方案。

要获得第一INT：

 匹配匹配= Regex.Match（3  -  .X  -  4，@\ D +）;
如果（match.Success）
    Console.WriteLine（int.Parse（match.Value））;
 

I need to parse a decimal integer that appears at the start of a string.

There may be trailing garbage following the decimal number. This needs to be ignored (even if it contains other numbers.)

e.g.

"1" => 1
" 42 " => 42
" 3 -.X.-" => 3
" 2 3 4 5" => 2

Is there a built-in method in the .NET framework to do this?

int.TryParse() is not suitable. It allows trailing spaces but not other trailing characters.

It would be quite easy to implement this but I would prefer to use the standard method if it exists.

foreach (var m in Regex.Matches(" 3 - .x. 4", @"\d+"))
{
    Console.WriteLine(m);
}

Updated per comments

Not sure why you don't like regular expressions, so I'll just post what I think is the shortest solution.

To get first int:

Match match = Regex.Match(" 3 - .x. - 4", @"\d+");
if (match.Success)
    Console.WriteLine(int.Parse(match.Value));