使用

一类的声明（这是另一个类的属性），它由一些属性。

我装入只是这个类的一个实例...

  PropertyGrid1.SelectedObject = oColumn
 

很显然，我不想手工打造code PropertyGrid中，我知道该怎么做。

但这里有一个问题。根据一个属性值，某些其它性能不应该是可见的，因为虽然我已经采用的

 ＆LT; System.ComponentModel.Browsable（假）＆GT; _
 

在属性声明属性。

反正有做到这一点编程，无需处理属性网格的所有建筑手动>

如果你希望一个gridItem.Hide（），那么，答案是否定的。只有这样，才能实现，在MS PropertyGrid中是动态发布通过类型转换器或自定义类型说明符的getProperties方法的属性（即实现了ICustomTypeDescriptor）。我会先尝试与类型转换器（expecially如果你要检查的属性值都在同一水平），有较少的代码做的。

Using

<System.ComponentModel.TypeConverter(GetType(System.ComponentModel.ExpandableObjectConverter))> _

on the declaration of a class (which is a property of another class) that consists of a number properties.

I load an instance of this class with simply ...

PropertyGrid1.SelectedObject = oColumn

Obviously I don't want to manually build the propertygrid in code, I know how to do that.

But here's the problem. Depending on the value of a property, certain other properties should not be visible, as though I'd used the

<System.ComponentModel.Browsable(False)> _

attribute on the property declaration.

Is there anyway to do this programmatically, without having to handle all the building of the property grid manually>

if you were hoping for a gridItem.Hide() then, the answer is no. The only way to achieve that in the MS PropertyGrid is to dynamically publish your properties through the GetProperties method of a TypeConverter or custom type descriptor (that implements ICustomTypeDescriptor). I would try first with the TypeConverter (expecially if the property values you want to check are at the same level), there is less coding to do.