我试图找出如何从一个多维数组得到一个单一的维度（为了便于讨论，让我们说这是2D），我有一个多维数组：

I'm trying to figure out how to get a single dimension from a multidimensional array (for the sake of argument, let's say it's 2D), I have a multidimensional array:

double[,] d = new double[,] { { 1, 2, 3, 4, 5 }, { 5, 4, 3, 2, 1 } };

如果这是一个交错数组，我只想叫 D [0] 那会给我 {1,2阵列， 3，4，5} ，是有办法，我可以实现同一个二维数组？

If it was a jagged array, I would simply call d[0] and that would give me an array of {1, 2, 3, 4, 5}, is there a way I can achieve the same with a 2D array?

推荐答案

没有。当然，你可以写一个包装类，再presents片，并具有内部索引器 - 但没有内置。另一种方法是编写一个方法，使一个切片，双手背矢量的复制 - 这取决于你是否想要一个的复制的或不

No. You could of course write a wrapper class that represents a slice, and has an indexer internally - but nothing inbuilt. The other approach would be to write a method that makes a copy of a slice and hands back a vector - it depends whether you want a copy or not.

using System;
static class ArraySliceExt
{
    public static ArraySlice2D<T> Slice<T>(this T[,] arr, int firstDimension)
    {
        return new ArraySlice2D<T>(arr, firstDimension);
    }
}
class ArraySlice2D<T>
{
    private readonly T[,] arr;
    private readonly int firstDimension;
    private readonly int length;
    public int Length { get { return length; } }
    public ArraySlice2D(T[,] arr, int firstDimension)
    {
        this.arr = arr;
        this.firstDimension = firstDimension;
        this.length = arr.GetUpperBound(1) + 1;
    }
    public T this[int index]
    {
        get { return arr[firstDimension, index]; }
        set { arr[firstDimension, index] = value; }
    }
}
public static class Program
{
    static void Main()
    {
        double[,] d = new double[,] { { 1, 2, 3, 4, 5 }, { 5, 4, 3, 2, 1 } };
        var slice = d.Slice(0);
        for (int i = 0; i < slice.Length; i++)
        {
            Console.WriteLine(slice[i]);
        }
    }
}