我试图运行Win7-64bit机器上的净套接字服务器code。 我不断收到以下错误：

I was trying to run a .Net socket server code on Win7-64bit machine . I keep getting the following error:

System.Net.Sockets.SocketException：一个地址与请求的协议不兼容   被使用。   错误code：10047

System.Net.Sockets.SocketException: An address incompatible with the requested protocol was used. Error Code: 10047

在code段是：

IPAddress ipAddress = Dns.GetHostEntry("localhost").AddressList[0];
IPEndPoint ip = new IPEndPoint(ipAddress, 9989);
Socket serverSocket = new Socket(AddressFamily.InterNetwork,SocketType.Stream, ProtocolType.Tcp);
try
{
    serverSocket.Bind(ip);
    serverSocket.Listen(10);
    serverSocket.BeginAccept(new AsyncCallback(AcceptConn), serverSocket);           
}
catch (SocketException excep)
{
  Log("Native code:"+excep.NativeErrorCode);
 // throw;
}    

以上code正常工作在Win-XP SP3。

The above code works fine in Win-XP sp3 .

我已经检查的MSDN 错误code细节但它并没有多大意义了我。

I have checked Error code details on MSDN but it doesn't make much sense to me.

任何人都遇到类似的问题？任何帮助？

Anyone has encountered similar problems? Any help?

推荐答案

在Windows Vista（和Windows 7），Dns.GetHostEntry也会返回IPv6地址。你的情况，IPv6地址（:: 1）首先在列表中。

On Windows Vista (and Windows 7), Dns.GetHostEntry also returns IPv6 addresses. In your case, the IPv6 address (::1) is first in the list.

您无法连接到IPv6（InterNetworkV6）使用IPv4（网际网络）插座解决。

You cannot connect to an IPv6 (InterNetworkV6) address with an IPv4 (InterNetwork) socket.

更改code创建套接字使用指定的IP地址的地址族：

Change your code to create the socket to use the address family of the specified IP address:

Socket serverSocket =
    new Socket(ipAddress.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
                        ↑

注意：有一个捷径获得的本地主机的IP地址：您可以简单地使用IPAddress.Loopback （127.0.0.1）或者IPAddress.IPv6Loopback （:: 1）。

Note: There's a shortcut to obtain the IP address of localhost: You can simply use IPAddress.Loopback (127.0.0.1) or IPAddress.IPv6Loopback (::1).