转换一个防爆pression树到源$ C ​​$ C字符串字符串、pression、树到源

2023-09-02 21:36:12 作者:怎拥

我有一个函数具有以下签名...

I have a function that has the following signature...

public string DoJunk(Expression<Func<bool>> expression)

我试图找到一种方式来恩pression参数转换回类似的东西原始出处code(或原烃源$ c。至少AC#重presentation $ C)。因此,如果有人调用函数像这样...

I'm trying to find a way to convert the "expression" parameter back to something resembling the original source code (or at least a c# representation of the original souce code). So, if someone calls the function like this...

DoJunk(() => (i + j) * 9 == Math.Round((double)j / (i - 3), 4))

...我希望能够转换前pression这...

...I'd like to be able to convert the expression to this...

(i + j) * 9 == Math.Round((double)j / (i - 3), 4)

有没有人这样做呢?

Has anyone done this?

推荐答案

下面是一个有趣的文章,用code,讨论EX pression树转换回一些类似于(大致)的原始来源:

Here's an interesting article, with code, discussing the conversion of expression trees back into something that resembles (roughly) the original source:

防爆pression树-Lambda表达式为codeDOM转换

作为一个侧面说明,你有没有打过电话的前$​​ P $ pssion的的ToString 的方法?

As a side-note, have you tried calling the expression's ToString method?

Expression<Func<int, int, bool>> expr =
    (i, j) => (i + j) * 9 == Math.Round((double)j / (i - 3), 4);

Console.WriteLine(expr.ToString());
// (i, j) => (Convert(((i + j) * 9)) = Round((Convert(j) / Convert((i - 3))), 4))

Console.WriteLine(expr.Body.ToString());
// (Convert(((i + j) * 9)) = Round((Convert(j) / Convert((i - 3))), 4))